CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard

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Solutions of Sample Papers for Class 10 Boards

Question 10 - CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at October 9, 2026 by

Question 10 — slide 26

Question 10 — slide 27

Question 10 — slide 28

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Transcript

Question 10 The diameter of a car wheel is 21 cm. The number of complete revolutions it will make in moving 66 km is: (A) 10โด (B) 10โต (C) 10โถ (D) 10โท Now, Number of revolutions = (๐‘ป๐’๐’•๐’‚๐’ ๐’…๐’Š๐’”๐’•๐’‚๐’๐’„๐’†)/(๐‘ซ๐’Š๐’”๐’•๐’‚๐’๐’„๐’† ๐’„๐’๐’—๐’†๐’“๐’†๐’… ๐’Š๐’ ๐Ÿ ๐’“๐’†๐’—๐’๐’๐’–๐’•๐’Š๐’๐’) Diameter of circle = 21 cm Radius = r = (๐Ÿ๐Ÿ)/(๐Ÿ) cm Circumference = 2ฯ€r Distance covered in one revolution = Circumference of wheel = 2๐…r = 2 ร—(22)/(7)ร—(21)/(2) = 66 cm Since Total Distance is in km, and our Distance in 1 revolution is in cm We convert Total distance in cm Now, Total Distance = 66 km = 66 ร— 1,000 m = 66,000 m = 66,000 ร— 100 cm = 66,00,000 cm Now , Number of revolutions = (๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘‘๐‘–๐‘ ๐‘ก๐‘Ž๐‘›๐‘๐‘’)/(๐ท๐‘–๐‘ ๐‘ก๐‘Ž๐‘›๐‘๐‘’ ๐‘๐‘œ๐‘ฃ๐‘’๐‘Ÿ๐‘’๐‘‘ ๐‘–๐‘› 1 ๐‘Ÿ๐‘’๐‘ฃ๐‘œ๐‘™๐‘ข๐‘ก๐‘–๐‘œ๐‘›) = (66,00,000)/(66) = 1,00,000 = 10^(5) So, the correct answer is (B)

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