CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard

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Question 5 - CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at October 9, 2026 by

Question 5 — slide 14

Question 5 — slide 15

Question 5 — slide 16

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Transcript

Question 5 The middle term of the A.P. 10, 7, 4, …, −62 is: (A) −26 (B) −29 (C) −32 (D) −35 To find the middle term, we need to first find the Number of terms Given AP 10, 7, 4, …, −62 Here a = 10 d = 7 – 10 = –3 And, a_(n) = –62 We need to find n Now, a_(n) = a + (n – 1) d Putting values –62 = 10 + (n – 1) × –3 –62 = 10 – 3n + 3 –62 = 13 – 3n 3n = 13 + 62 3n = 75 n = (75)/(3) n = 25 Thus, Number of terms is 25 Now, we need to find Middle term Middle term = ((𝑛+1)/(2))^(𝑡ℎ) term = (25 + 1)/(2) = (26)/(2) = 13^(th) term Finding Middle term (13^(th) term) Putting n = 13, a = 10, d = –3 in a_(n) = a + (n – 1) d a_(13) = 10 + (13 – 1) × –3 a_(13) = 10 + 12 × –3 a_(13) = 10 – 36 a_(13) = –26 Thus, Middle term is –26 So, correct answer is (A)

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