CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard

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Question 6 - CBSE Class 10 Sample Paper for 2027 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at October 9, 2026 by

Question 6 — slide 17

Question 6 — slide 18

Question 6 — slide 19

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Transcript

Question 6 The perimeters of two similar triangles are 56 cm and 70 cm respectively. If one side of the first triangle is 14 cm, then the corresponding side of the second triangle (in cm) is: (A) 5 (B) 7.5 (C) 10 (D) 17.5 For two similar triangles, Ratio of sides = Ratio of their perimeters Thus, we can write (𝑺𝒊𝒅𝒆 𝒐𝒇 𝟏^(𝒔𝒕) 𝑻𝒓𝒊𝒂𝒏𝒈𝒍𝒆)/(𝑺𝒊𝒅𝒆 𝒐𝒇 𝟐^(𝒏𝒅) 𝑻𝒓𝒊𝒂𝒏𝒈𝒍𝒆)= (𝑷𝒆𝒓𝒊𝒎𝒆𝒕𝒆𝒓 𝒐𝒇 𝟏^(𝒔𝒕) 𝑻𝒓𝒊𝒂𝒏𝒈𝒍𝒆)/(𝑷𝒆𝒓𝒊𝒎𝒆𝒕𝒆𝒓 𝒐𝒇 𝟐^(𝒏𝒅) 𝑻𝒓𝒊𝒂𝒏𝒈𝒍𝒆) (14)/(𝑆𝑖𝑑𝑒 𝑜𝑓 2^(𝑛𝑑) 𝑇𝑟𝑖𝑎𝑛𝑔𝑙𝑒)= (56)/(70) (14)/(𝑆𝑖𝑑𝑒 𝑜𝑓 2^(𝑛𝑑) 𝑇𝑟𝑖𝑎𝑛𝑔𝑙𝑒)= (4)/(5) 14 × (5)/(4) = Side of 2^(nd) Triangle 7 × (5)/(2) = Side of 2^(nd) Triangle (35)/(2) = Side of 2^(nd) Triangle 17.5 = Side of 2^(nd) Triangle Side of 2^(nd) Triangle = 17.5 cm So, correct answer is (D) 14 × (5)/(4) = Side of 2^(nd) Triangle 7 × (5)/(2) = Side of 2^(nd) Triangle (35)/(2) = Side of 2^(nd) Triangle 17.5 = Side of 2^(nd) Triangle Side of 2^(nd) Triangle = 17.5 cm So, correct answer is (D) Similar https://www.teachoo.com/12366/3414/Question-30--Choice---1/category/CBSE-Class-10-Sample-Paper-for-2021-Boards---Maths-Standard/

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