# Misc 29 - Chapter 9 Class 11 Sequences and Series

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 29 A person writes a letter to four of his friends. He asks each one of them to copy the letter and mail to four different persons with instruction that they move the chain similarly. Assuming that the chain is not broken and that it costs 50 paise to mail one letter. Find the amount spent on the postage when 8th set of letter is mailed. Hence, the sequence is i.e. 4, 16, 64, , This is a G.P. as 16/4 = 4 & 64/16 = 4 Common ratio = r = 4 First term = a = 4 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 r = 4 & a = 4 We need to find number of total letters mailed upto 8th set of letters i.e. S8 For r > 1 Sn = (a( ^ 1))/(r 1) Putting values of a = 4 , r = 4 & n = 8 S8 = (4(48 1))/(4 1) = (4(48 1))/3 = (4(65536 1))/3 = (4(65535))/3 = 4(21845) = 87380 Hence, total number of letters posted after 8th set is 87380 Given that postage spent 50 paise per letter Hence the amount spend on the postage of 87380 letter is = Rs 50/100 87380 = Rs 43690 Hence , the amount spent on the postage when 8th set of letter is mailed is Rs 43690

Misc 1

Misc 2

Misc 3 Important

Misc 4

Misc 5

Misc 6

Misc 7 Important

Misc 8

Misc 9

Misc 10

Misc 11

Misc 12

Misc 13

Misc 14

Misc 15

Misc 16 Important

Misc 17

Misc 18

Misc 19 Important

Misc 20

Misc 21

Misc 22

Misc 23

Misc 24

Misc 25 Important

Misc 26

Misc 27

Misc 28 Important

Misc 29 You are here

Misc 30

Misc 31

Misc 32 Important

Chapter 9 Class 11 Sequences and Series

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.