


Miscellaneous
Misc 2
Misc 3 Important
Misc 4
Misc 5
Misc 6 Important
Misc 7 Important
Misc 8
Misc 9
Misc 10 Important
Misc 11
Misc 12
Misc 13
Misc 14 Important
Misc 15
Misc 16 Important
Misc 17
Misc 18
Misc 19 Important
Misc 20
Misc 21 (i) Important
Misc 21 (ii)
Misc 22 Important
Misc 23 Important
Misc 24 Deleted for CBSE Board 2022 Exams
Misc 25 Important Deleted for CBSE Board 2022 Exams
Misc 26 Deleted for CBSE Board 2022 Exams
Misc 27
Misc 28 Important You are here
Misc 29 Important
Misc 30
Misc 31 Important
Misc 32 Important
Misc 28 Shamshad Ali buys a scooter for Rs 22000. He pays Rs 4000 cash and agrees to pay the balance in annual installment of Rs 1000 plus 10% interest on the unpaid amount. How much will the scooter cost him? Amount paid to buy scooter = Rs 22000 He pay cash = Rs 4000 Remaining balance = Rs 22000 β Rs 4000 = Rs 18000 Annual instalment = 1000 + "Interest on unpaid amount @10%" Thus , our instalments are 2800 , 2700 , 2600,β¦ Total number of instalments = (π ππππππππ πππππππ ππππ‘)/(π΅ππππππ πππππππ πππ πππ π‘ππππππ‘) = 18000/1000 = 18 So, our instalments are 2800 , 2700 , 2600 , β¦ to 18 terms We can observe that this is an AP as difference between consecutive terms is an AP Here first term (a) = 2800 common difference = d = 2700 β 2800 = β 100 number of terms = n = 18 We need to calculate total amount paid in 18 instalments i.e. (2800 + 2700 +2600 + β¦ to 18 terms) We use the formula, Sn = π/2 (2a + (n β 1)d) Where, Sn = sum of n terms of A.P. n = number of terms a = first term and d = common difference Putting value of n = 18 , a = 2800 & d = β100 S18 = 18/2 [ 2(2800)+(18 β 1) (-100) ] = 9[ 5600 + 17(-100)] = 9[ 5600 β 1700] = 9(3900) = 35100 Hence, amount paid in 18 instalments = Rs 35100 Total amount paid by him = Amount paid earlier + Amount paid in 18 instalments = 4000 + 35100 = Rs 39100