Question 37 (ii) - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at Sept. 2, 2025 by Teachoo

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Question 37 (ii) Find the critical points of 𝑃(𝑥).To find critical points, we find values of x where P’(x) = 0 Now, P(𝑥) = −0.8𝑥^2+30𝑥−150 Diff w.r.t x P’(𝑥) = 𝑑(−0.8𝑥^2 + 30𝑥 − 150" " )/𝑑𝑥 P’(𝑥) = −0.8 × 2𝑥+30 P’(𝑥) = −1.6𝑥+30 Putting P’(𝒙) = 0 −1.6𝑥+30=0 −1.6𝑥=−30 𝑥=30/1.6 𝑥=30/(16/10) 𝑥=30/16 × 10 𝑥=30/16 × 10 𝒙=𝟏𝟖.𝟕𝟓 Thus, 𝟏𝟖.𝟕𝟓 is the critical point of P(x)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo

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