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Question 34 (A) Solve the differential equation: 𝑦+𝑑/𝑑π‘₯(π‘₯𝑦)=π‘₯(sin π‘₯+π‘₯)Now, our equation is 𝑦+𝑑/𝑑π‘₯(π‘₯𝑦)=π‘₯(sin π‘₯+π‘₯) Using product formula 𝑦+(𝑑(π‘₯))/𝑑π‘₯ 𝑦+π‘₯ 𝑑𝑦/𝑑π‘₯=π‘₯(sin π‘₯+π‘₯) 𝑦+𝑦+π‘₯ 𝑑𝑦/𝑑π‘₯=π‘₯(sin π‘₯+π‘₯) π‘₯ 𝑑𝑦/𝑑π‘₯+2𝑦=π‘₯(sin π‘₯+π‘₯) Diving both sides by x π‘₯/π‘₯ \ Γ— 𝑑𝑦/𝑑π‘₯+2𝑦/π‘₯=π‘₯(sin π‘₯+π‘₯)/π‘₯ 𝑑𝑦/𝑑π‘₯+2𝑦/π‘₯=(sin π‘₯+π‘₯) Comparing with 𝑑𝑦/𝑑π‘₯ + Py = Q P = 𝟐/𝒙 & Q = (π’”π’Šπ’ 𝒙+𝒙) Finding Integrating factor (IF) IF = e^∫1▒𝑝𝑑π‘₯ = 𝒆^∫1β–’γ€–πŸ/𝒙 𝒅𝒙〗 = e^(2∫1β–’γ€–1/π‘₯ 𝑑π‘₯γ€—) = 𝒆^(𝟐 π’π’π’ˆβ‘|𝒙| ) = e^log⁑〖π‘₯^2 γ€— = 𝒙^𝟐 Solution of differential equation is y Γ— IF = ∫1▒〖𝑄.𝐼𝐹 𝑑π‘₯γ€— Putting values y Γ— x2 = ∫1β–’γ€–(π’”π’Šπ’ 𝒙+𝒙) 𝒙^𝟐 𝒅𝒙 γ€— yx2 = ∫1▒〖𝑠𝑖𝑛⁑π‘₯ Γ— π‘₯^2 γ€— 𝑑π‘₯+∫1▒𝒙^πŸ‘ 𝒅𝒙 yx2 = ∫1▒〖𝑠𝑖𝑛⁑π‘₯ Γ— π‘₯^2 γ€— 𝑑π‘₯+π‘₯^4/4+𝐢 yx2 = ∫1▒〖𝒙^𝟐 π’”π’Šπ’β‘π’™ γ€— 𝒅𝒙+𝒙^πŸ’/πŸ’+π‘ͺ Evaluating ∫1▒〖𝒙^𝟐 π’”π’Šπ’β‘π’™ γ€— 𝒅𝒙 separately ∫1β–’γ€–π‘₯^2 sin⁑π‘₯ γ€— 𝑑π‘₯ We know that ∫1▒〖𝑓(π‘₯) 𝑔⁑(π‘₯) γ€— 𝑑π‘₯=𝑓(π‘₯) ∫1▒𝑔(π‘₯) 𝑑π‘₯βˆ’βˆ«1β–’(𝑓^β€² (π‘₯) ∫1▒𝑔(π‘₯) 𝑑π‘₯) 𝑑π‘₯ Putting f(x) = x2 and g(x) = sin x ∫1β–’γ€–π‘₯^2 sin⁑π‘₯ γ€— 𝑑π‘₯=𝒙^𝟐 ∫1▒𝐬𝐒𝐧⁑𝒙 π’…π’™βˆ’βˆ«1β–’(𝒅(𝒙^𝟐 )/𝒅𝒙 ∫1β–’γ€–π’”π’Šπ’β‘π’™ 𝒅𝒙〗) 𝒅𝒙 = βˆ’ π‘₯^2 cos⁑π‘₯ βˆ’ ∫1β–’γ€–2π‘₯ Γ— βˆ’cos⁑〖π‘₯ 𝑑π‘₯γ€— γ€— = βˆ’ π‘₯^2 cos⁑π‘₯+2 ∫1▒〖𝒙 𝒄𝒐𝒔⁑𝒙 γ€— 𝒅𝒙+𝐢 Applying by parts again in ∫1▒〖𝒙 𝒄𝒐𝒔⁑𝒙 γ€— = βˆ’ π‘₯^2 cos⁑π‘₯+2 [π’™βˆ«1▒𝒄𝒐𝒔⁑𝒙 π’…π’™βˆ’βˆ«1β–’(𝒅𝒙/𝒅𝒙 ∫1▒〖𝒄𝒐𝒔⁑𝒙 𝒅𝒙〗) 𝒅𝒙]+𝐢 = βˆ’ π‘₯^2 cos⁑π‘₯+2 [𝒙 π’”π’Šπ’ π’™βˆ’βˆ«1β–’γ€–πŸ Γ— π’”π’Šπ’ 𝒙〗 𝒅𝒙]+𝐢 = βˆ’ π‘₯^2 cos⁑π‘₯+2 [π‘₯ 𝑠𝑖𝑛 π‘₯βˆ’βˆ«1β–’γ€–π’”π’Šπ’ 𝒙〗 𝒅𝒙]+𝐢 = βˆ’ π‘₯^2 cos⁑π‘₯+2 [π‘₯ 𝑠𝑖𝑛 π‘₯βˆ’(βˆ’π‘π‘œπ‘  π‘₯) ]+𝐢 = βˆ’ 𝒙^𝟐 𝒄𝒐𝒔⁑𝒙+𝟐 [𝒙 π’”π’Šπ’ 𝒙+πœπ¨π¬β‘π’™ ]+π‘ͺ Putting value of ∫1β–’γ€–π‘₯^2 sin⁑π‘₯ γ€— 𝑑π‘₯ in (1) yx2 = ∫1β–’γ€–π‘₯^2 𝑠𝑖𝑛⁑π‘₯ γ€— 𝑑π‘₯+π‘₯^4/4+𝐢 yx2 = βˆ’ 𝒙^𝟐 𝒄𝒐𝒔⁑𝒙+𝟐 [𝒙 π’”π’Šπ’ 𝒙+πœπ¨π¬β‘π’™ ]+𝒙^πŸ’/πŸ’+π‘ͺ Which is the required solution

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo