Question 14 - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at August 26, 2025 by Teachoo

The distance of the point with position vector 3ı ˆ+4ȷ ˆ+5𝑘 ˆ from - CBSE Class 12 Sample Paper for 2026 Boards

part 2 - Question 14 - CBSE Class 12 Sample Paper for 2026 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Question 14 The distance of the point with position vector 3𝚤 ˆ+4𝚥 ˆ+5𝑘 ˆ from the y -axis is (A) 4 units (B) √34 units (C) 5 units (D) 5√2 unitsFormula To find the distance of a point P with coordinates (𝒙,𝒚,𝒛) from one of the coordinate axes, we use the following formulas for the perpendicular distance: Distance from the 𝒙-axis =√(𝑦^2+𝑧^2 ) Distance from the 𝒚-axis =√(𝑥^2+𝑧^2 ) Distance from the 𝒛-axis =√(𝑥^2+𝑦^2 ) For this question, we need formula for distance from the 𝐲-axis. point is on y-axis its x & z coordinate is 0 Let the point on y-axis be A(0, a, 0) Given that We need to find stance of Point A is at a distance of 5√2 from point P (3, – 2, 5) i.e. PA = 5√2 Finding Distance PA Since the a point is on the y-axis, then the coordinate of x and y are 0. So, the point is (0, y, 0) The distance of the point with position vector 3ı ˆ+4ȷ ˆ+5𝑘 ˆ from the y -axis is So, the correct answer is (B)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo

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