
CBSE Class 12 Sample Paper for 2026 Boards
CBSE Class 12 Sample Paper for 2026 Boards
Last updated at Aug. 26, 2025 by Teachoo
Transcript
Question 8 If π(π₯)=π₯tan^(β1) π₯, then π^β² (1) is equal to (A) π/4β1/2 (B) π/4+1/2 (C) βπ/4β1/2 (D) βπ/4+1/2Given π(π₯)=π₯tan^(β1) π₯ Now, π^β² (π)=(π₯tan^(β1) π₯)^β² Using product rule =(π₯)^β² tan^(β1) π₯+π₯ (tan^(β1)β‘π₯ )^β² =1 Γ γπ‘ππγ^(β1) π₯+π₯ Γ1/(1 + π₯^2 ) =γπππγ^(βπ) π+π/(π + π^π ) Now, π^β² (π)=γπ‘ππγ^(β1) (1) +1/(1 + 1^2 ) =γπ‘ππγ^(β1) (1) +1/(1 + 1) =γπ‘ππγ^(β1) (1) +1/2 =π /π +π/π So, the correct answer is (B)