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Question 6 Value of the determinant |■(cos 67^∘&sin 67^∘@sin 23^∘&cos 23^∘ )| is (A) 0 (B) 1/2 (C) √3/2 (D) 1Now, |■(cos 67^∘&sin 67^∘@sin 23^∘&cos 23^∘ )| =cos⁡〖67° 〗 cos⁡〖23° 〗−sin⁡〖23° 〗 sin⁡〖67° 〗 Using cos (A + B) = cos A cos B – sin A sin B =𝒄𝒐𝒔⁡〖(𝟔𝟕°+𝟐𝟑°)〗 =cos⁡〖90° 〗 =𝟎 So, the correct answer is (A)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo