How many grams of Magnesium Sulphate are present in 135g of solid left by evaporation of sea water?  

(A) 6g 

(B) 12g 

(C) 18g 

(D) 24g 

 

Answer - 

 

From our table

Q 49 - compound in the table reacts with acids - Teachoo.jpg

  • In 45 g solid, we have 6g Magnesium Sulphate
  • In 1 g solid, we have 6/45 g Magnesium Sulphate
  • In 135 g solid, we have 6/45 × 135 g = 6 × 3 = 18g  Magnesium Sulphate

 

So, the correct answer is (c)

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About the Author

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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 11 years and a teacher from the past 11 years. He teaches Science, Accounts and English at Teachoo