Ex 2.4, 8 (ii) - Chapter 2 Class 9 Polynomials
Last updated at Dec. 16, 2024 by Teachoo
Ex 2.4
Ex 2.4, 1 (i)
You are here
You are here
Chapter 2 Class 9 Polynomials
Serial order wise
- Ex 2.1
- Ex 2.2
- Ex 2.3
-
Ex 2.4
- Examples
- Remainder Theorem
Transcript
Ex 2.4, 8 Factorise each of the following: (ii) 8a3 – b3 – 12a2b + 6ab2 8a3 – b3 – 12a2b + 6ab2 = (2a)3 – (b)3 – 12a2b + 6ab2 = (2a)3 + (b)3 – 6ab (2a – b) = (2a)3 – (b)3 – 3(2a)(b) (2a – b) Using (x – y)3 = x3 – y3 – 3xy(x – y) Putting x = 2a, y = b = (2a – b)3 = (2a – b) (2a – b) (2a – b)
