Ex 1.1, 1 (ii) Class 12 - Given R = {(x, y): y = x + 5 and x < 4} - Ex 1.1

part 2 - Ex 1.1, 1 (ii) - Ex 1.1 - Serial order wise - Chapter 1 Class 12 Relation and Functions
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Ex 1.1, 1 Determine whether each of the following relations are reflexive, symmetric and transitive: (ii) Relation R in the set N of natural numbers defined as R = {(x, y): y = x + 5 and x < 4} R = {(x, y): y = x + 5 and x < 4} Here x & y are natural numbers, & x < 4 So, we take value of x as 1 , 2, 3 ∴ R = {(1, 6), (2, 7), (3, 8)} Check Reflexive If the relation is reflexive, then (a, a) ∈ R for every a ∈ N Since (1, 1) ∉ R ∴ R is not reflexive Check symmetric To check whether symmetric or not, If (a, b) ∈ R, then (b, a) ∈ R Here (1, 6) ∈ R , but (6, 1) ∉ R ∴ R is not symmetric Check transitive To check whether transitive or not, If (a, b) ∈ R & (b, c) ∈ R , then (a, c) ∈ R There is no pair in R such that (a, b) ∈ R and (b, c) ∈ R , then (a, c) ∉ R. ∴ R is not transitive Hence, R is neither reflexive, nor symmetric, nor transitive.

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