Question 1 - Miscellaneous - Chapter 9 Class 12 Differential Equations
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 1 From the differential equation representing the family of curves given by (๐ฅโ๐)^2+2๐ฆ^2=๐^2, where ๐ is an arbitrary constant (๐ฅโ๐)^2+2๐ฆ^2=๐^2 Differentiating w.r.t. ๐ฅ ใ[(๐ฅโ๐)^2]ใ^โฒ+(2๐ฆ^2 )^โฒ=(๐^2 )^โฒ 2(๐ฅโ๐)+2ร2๐ฆ๐ฆ^โฒ=0 (๐ฅโ๐)+2๐ฆ๐ฆ^โฒ=0 ๐ฅ+2๐ฆ๐ฆ^โฒ=๐ ๐=๐ฅ+2ใ๐ฆ๐ฆใ^โฒ Since it has one variable, we will differentiate once a = 2๐ฆ ๐๐ฆ/๐๐ฅ+๐ฅ Putting value of a in (๐ฅโ๐)^2+2๐ฆ^2=๐^2 [๐ฅโ(๐ฅ+2๐ฆ๐ฆ^โฒ)]^2+2๐ฆ^2=ใ(๐ฅ+2๐ฆ๐ฆ^โฒ)ใ^2 (โ2๐ฆ๐ฆ^โฒ )^2+2๐ฆ^2=ใ(๐ฅ+2๐ฆ๐ฆ^โฒ)ใ^2 4๐ฆ^2 ใ๐ฆ^โฒใ^2+2๐ฆ^2=๐ฅ^2+4๐ฆ^2 ใ๐ฆ^โฒใ^2+4๐ฅ๐ฆ๐ฆ^โฒ 2๐ฆ^2=๐ฅ^2+4๐ฅ๐ฆ๐ฆ^โฒ 2๐ฆ^2โ๐ฅ^2=4๐ฅ๐ฆ๐ฆ^โฒ (2๐ฆ^2โ ๐ฅ^2)/4๐ฅ๐ฆ=๐ฆ^โฒ ๐^โฒ=(๐๐^๐ โ ๐^๐)/๐๐๐
Miscellaneous
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo