Last updated at Dec. 16, 2024 by Teachoo
Misc 2 For each of the exercise given below , verify that the given function (๐๐๐๐๐๐๐๐ก ๐๐ ๐๐ฅ๐๐๐๐๐๐ก) is a solution of the corresponding differential equation . (i) ๐ฅ๐ฆ=๐ ๐^๐ฅ+๐ ๐^(โ๐ฅ)+๐ฅ^2 : ๐ฅ (๐^2 ๐ฆ)/(๐๐ฅ^2 )+2 ๐๐ฆ/๐๐ฅโ๐ฅ๐ฆ+๐ฅ^2โ2=0 ๐ฅ๐ฆ=๐๐^๐ฅ+๐ ๐^(โ๐ฅ)+๐ฅ^2 Differentiating w.r.t x (๐(๐ฅ๐ฆ))/๐๐ฅ=๐/๐๐ฅ [๐ ๐^๐ฅ+๐ ๐^(โ๐ฅ)+๐ฅ^2 ] ๐๐ฅ/๐๐ฅ y+๐๐ฆ/๐๐ฅ ๐ฅ =๐ใ ๐ใ^๐ฅ+(โ1)๐ ๐^(โ๐ฅ)+2๐ฅ ๐+๐^โฒ ๐ =๐ใ ๐ใ^๐โ๐ ๐^(โ๐)+๐๐ Differentiating again w.r.t x ๐ฆโฒ+(๐ฆ^โฒ ๐ฅ)^โฒ =(๐๐^๐ฅ )^โฒโ(๐๐^(โ๐ฅ) )^โฒ+(2๐ฅ)^โฒ ๐ฆ^โฒ+(๐ฆ^โฒโฒ ๐ฅ+๐ฆ^โฒร1)=๐๐^๐ฅ+๐๐^(โ๐ฅ)+2 ๐^โฒโฒ ๐+๐๐^โฒ=๐๐^๐+๐๐^(โ๐)+๐ Now, we know that ๐ฅ๐ฆ=๐๐^๐ฅ+๐ ๐^(โ๐ฅ)+๐ฅ^2 ๐ฅ๐ฆโ๐ฅ^2=๐๐^๐ฅ+๐ ๐^(โ๐ฅ) ๐๐^๐+๐ ๐^(โ๐)=๐๐โ๐^๐ Putting (2) in (1) ๐ฆ^โฒโฒ ๐ฅ+2๐ฆ^โฒ=๐๐^๐+๐๐^(โ๐)+2 ๐ฆ^โฒโฒ ๐ฅ+2๐ฆ^โฒ=๐๐โ๐^๐+2 (๐^2 ๐ฆ)/(๐๐ฅ^2 ) ๐ฅ+2 ๐๐ฆ/๐๐ฅ=๐๐โ๐^๐+2 (๐ ^๐ ๐)/(๐ ๐^๐ ) ๐+๐ ๐ ๐/๐ ๐โ๐๐+๐^๐=๐ โด The given function is a solution
Miscellaneous
Misc 1 (ii)
Misc 1 (iii) Important
Misc 2 (i) You are here
Misc 2 (ii) Important
Misc 2 (iii)
Misc 2 (iv) Important
Misc 3 Important
Misc 4
Misc 5 Important
Misc 6
Misc 7 Important
Misc 8 Important
Misc 9
Misc 10 Important
Misc 11
Misc 12 Important
Misc 13 (MCQ)
Misc 14 (MCQ) Important
Misc 15 (MCQ)
Question 1
Question 2 Important
Question 3 Important
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo