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Ex 3.2, 11 If x [■8(2@3)] + y [■8(−1@1)] = [■8(10@5)] , find values of x and y. x [■8(2@3)] + y [■8(−1@1)] = [■8(10@5)] [■8(2𝑥@3𝑥)] + [■8(−𝑦@𝑦)] = [■8(10@5)] [■8(𝟐𝒙−𝒚@𝟑𝒙+𝒚)] = [■8(𝟏𝟎@𝟓)] Since the matrices are equal. corresponding elements are equal 2x − y = 10 3x + y = 5 Solving equations Adding (1) & (2) (2x – y) + (3x + y) = 10 + 5 2x – y + 3x + y = 15 2x + 3x – y + y = 15 5x + 0 = 15 x = 15/5 x = 3 Putting value of x in (1) 2x – y = 10 2(3) – y = 10 6 – y = 10 –y = 10 – 6 –y = 4 y = –4 Hence, x = 3 & y = –4

  1. Chapter 3 Class 12 Matrices
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo