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Transcript

Ex 12.3, 5 Factorise the expressions and divide them as directed. (vii) 39๐‘ฆ^3(50๐‘ฆ^2 โ€“ 98) รท 26๐‘ฆ^2 (5y + 7)We first factorise ใ€–39๐‘ฆใ€—^3 (50๐‘ฆ^2โˆ’ 98) = ใ€–39๐‘ฆใ€—^3 (2ร—ใ€–25๐‘ฆใ€—^2 โˆ’ 2 ร— 49) Taking 2 common = ใ€–39๐‘ฆใ€—^3ร—2 (ใ€–25๐‘ฆใ€—^2โˆ’49) = ใ€–78๐‘ฆใ€—^3 (ใ€–25๐‘ฆใ€—^2โˆ’49) = ใ€–๐Ÿ•๐Ÿ–๐’šใ€—^๐Ÿ‘ [(ใ€–๐Ÿ“๐’šใ€—^๐Ÿ)โˆ’(๐Ÿ•)^๐Ÿ] = ใ€–78๐‘ฆใ€—^3 (5y โˆ’ 7) (5y + 7) Dividing 39๐‘ฆ^3(50๐‘ฆ^2 โ€“ 98) รท 26๐‘ฆ^2 (5y + 7) = (39๐‘ฆ^3 (50๐‘ฆ^2 โˆ’ 98))/(26๐‘ฆ^2 (5๐‘ฆ + 7)) = (๐Ÿ•๐Ÿ–๐’š^๐Ÿ‘ (๐Ÿ“๐’š + ๐Ÿ•) (๐Ÿ“๐’š โˆ’ ๐Ÿ•))/(๐Ÿ๐Ÿ”๐’š^๐Ÿ (๐Ÿ“๐’š + ๐Ÿ•)) = 78/26 ร— ๐‘ฆ^3/๐‘ฆ^2 ร— ((5๐‘ฆ + 7))/((5๐‘ฆ + 7)) ร— (5y โˆ’ 7) = 3 ร— y ร— (5y โˆ’7) = 3y (5y โˆ’ 7)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.