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Ex 14.3, 5 (vii) - Factorise and divide 39y^3 (50y^2 - 98) รท 26y2(5y+7

Ex 14.3, 5 (vii) - Chapter 14 Class 8 Factorisation - Part 2

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Ex 14.3, 5 Factorise the expressions and divide them as directed. (vii) 39๐‘ฆ^3(50๐‘ฆ^2 โ€“ 98) รท 26๐‘ฆ^2 (5y + 7) We first factorise ใ€–39๐‘ฆใ€—^3 (50๐‘ฆ^2โˆ’ 98) = ใ€–39๐‘ฆใ€—^3 (2ร—ใ€–25๐‘ฆใ€—^2 โˆ’ 2 ร— 49) Taking 2 common = ใ€–39๐‘ฆใ€—^3ร—2 (ใ€–25๐‘ฆใ€—^2โˆ’49) = ใ€–78๐‘ฆใ€—^3 (ใ€–25๐‘ฆใ€—^2โˆ’49) = ใ€–78๐‘ฆใ€—^3 [(ใ€–5๐‘ฆใ€—^2)โˆ’(7)^2] Using ๐‘Ž^2 โˆ’ ๐‘^2 = (a + b) (a โˆ’ b) Here ๐‘Ž= z and b = 4 Dividing 39๐‘ฆ^3(50๐‘ฆ^2 โ€“ 98) รท 26๐‘ฆ^2 (5y + 7) = (39๐‘ฆ^3 (50๐‘ฆ^2 โˆ’ 98))/(26๐‘ฆ^2 (5๐‘ฆ + 7)) = (78๐‘ฆ^3 (5๐‘ฆ + 7) (5๐‘ฆ โˆ’ 7))/(26๐‘ฆ^2 (5๐‘ฆ + 7)) = 78/26 ร— ๐‘ฆ^3/๐‘ฆ^2 ร— ((5๐‘ฆ + 7))/((5๐‘ฆ + 7)) ร— (5y โˆ’ 7) = 3 ร— y ร— (5y โˆ’7) = 3y (5y โˆ’ 7)

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