
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 12.3
Ex 12.3, 1 (ii) Important
Ex 12.3, 1 (iii)
Ex 12.3, 1 (iv) Important
Ex 12.3, 1 (v)
Ex 12.3, 2 (i)
Ex 12.3, 2 (ii) Important You are here
Ex 12.3, 2 (iii) Important
Ex 12.3, 2 (iv)
Ex 12.3, 2 (v) Important
Ex 12.3, 3 (i)
Ex 12.3, 3 (ii)
Ex 12.3, 3 (iii) Important
Ex 12.3, 3 (iv)
Ex 12.3, 3 (v) Important
Ex 12.3, 4 (i)
Ex 12.3, 4 (ii) Important
Ex 12.3, 4 (iii)
Ex 12.3, 4 (iv)
Ex 12.3, 4 (v) Important
Ex 12.3, 5 (i)
Ex 12.3, 5 (ii) Important
Ex 12.3, 5 (iii)
Ex 12.3, 5 (iv) Important
Ex 12.3, 5 (v)
Ex 12.3, 5 (vi)
Ex 12.3, 5 (vii) Important
Last updated at Aug. 8, 2023 by Teachoo
Ex 12.3, 2 (Method 1) Divide the given polynomial by the given monomial. (ii) (3๐ฆ^8 โ 4๐ฆ^6 + 5๐ฆ^4) รท ๐ฆ^43๐ฆ^8 โ 4๐ฆ^6 + 5๐ฆ^4 = (3๐ฆ^4ร๐ฆ^4 ) โ (4y^2ร๐ฆ^4 )+(5รy^4) Taking ๐ฆ^4 common = ๐ฆ^4 (3๐ฆ^4 โ 4๐ฆ^2+5) Dividing (3๐ฆ^8 โ 4๐ฆ^6 + 5๐ฆ^4)/๐ฆ^4 = (๐ฆ^4 (3๐ฆ^4 โ ใ4๐ฆใ^4 + 5))/๐ฆ^4 = ๐๐^๐ โ ๐๐^๐ + ๐ Ex 12.3, 2 (Method 2) Divide the given polynomial by the given monomial. (ii) (3๐ฆ^8 โ 4๐ฆ^6 + 5๐ฆ^4) รท ๐ฆ^4 (3๐ฆ^8 โ 4๐ฆ^6 + 5๐ฆ^4)/๐ฆ^4 = (๐๐^๐)/๐^๐ โใ๐๐ใ^๐/๐^๐ +(๐๐^๐)/๐^๐ = 3ร๐ฆ^(8 โ 4)โ 4ร ๐ฆ^(6 โ 4)+5ร๐ฆ^(4 โ 4) = 3ร๐ฆ^4โ 4ร ๐ฆ^2+ใ5๐ฆใ^0 = ใ๐๐ใ^๐ โ ๐๐^๐+๐ (๐ด๐ ๐^๐/๐^๐ =๐^(๐ โ n) ) (As ๐^0=1)