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  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Ex 14.3, 2 (Method 1) Divide the given polynomial by the given monomial. (ii) (3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4) รท ๐‘ฆ^4 3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4 = (3๐‘ฆ^4ร—๐‘ฆ^4 ) โˆ’ (4y^2ร—๐‘ฆ^4 )+(5ร—y^4) Taking ๐‘ฆ^4 common = ๐‘ฆ^4 (3๐‘ฆ^4 โˆ’ 4๐‘ฆ^2+5) Dividing (3๐‘ฆ^8 โˆ’ 4๐‘ฆ^6 + 5๐‘ฆ^4)/๐‘ฆ^4 = (๐‘ฆ^4 (3๐‘ฆ^4 โˆ’ ใ€–4๐‘ฆใ€—^4 + 5))/๐‘ฆ^4 = ๐Ÿ‘๐’š^๐Ÿ’ โˆ’ ๐Ÿ’๐’š^๐Ÿ + ๐Ÿ“ Ex 14.3, 2 (Method 2) Divide the given polynomial by the given monomial. (ii) (3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4) รท ๐‘ฆ^4 (3๐‘ฆ^8 โˆ’ 4๐‘ฆ^6 + 5๐‘ฆ^4)/๐‘ฆ^4 = (3๐‘ฆ^8)/๐‘ฆ^4 โˆ’ใ€–4๐‘ฆใ€—^6/๐‘ฆ^4 +(5๐‘ฆ^4)/๐‘ฆ^4 = 3ร—๐‘ฆ^(8 โˆ’ 4)โˆ’ 4ร— ๐‘ฆ^(6 โˆ’ 4)+5ร—๐‘ฆ^(4 โˆ’ 4) = 3ร—๐‘ฆ^4โˆ’ 4ร— ๐‘ฆ^2+ใ€–5๐‘ฆใ€—^0 = ใ€–๐Ÿ‘๐’šใ€—^๐Ÿ’ โˆ’ ๐Ÿ’๐’š^๐Ÿ+๐Ÿ“ (๐ด๐‘  ๐‘Ž^๐‘š/๐‘Ž^๐‘› =๐‘Ž^(๐‘š โˆ’ n) ) (As ๐‘Ž^0=1)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.