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Ex 14.3, 5 (vi) - Chapter 14 Class 8 Factorisation
Last updated at March 23, 2023 by Teachoo
Ex 14.3
Ex 14.3, 1 (i)
Ex 14.3, 1 (ii) Important
Ex 14.3, 1 (iii)
Ex 14.3, 1 (iv) Important
Ex 14.3, 1 (v)
Ex 14.3, 2 (i)
Ex 14.3, 2 (ii) Important
Ex 14.3, 2 (iii) Important
Ex 14.3, 2 (iv)
Ex 14.3, 2 (v) Important
Ex 14.3, 3 (i)
Ex 14.3, 3 (ii)
Ex 14.3, 3 (iii) Important
Ex 14.3, 3 (iv)
Ex 14.3, 3 (v) Important
Ex 14.3, 4 (i)
Ex 14.3, 4 (ii) Important
Ex 14.3, 4 (iii)
Ex 14.3, 4 (iv)
Ex 14.3, 4 (v) Important
Ex 14.3, 5 (i)
Ex 14.3, 5 (ii) Important
Ex 14.3, 5 (iii)
Ex 14.3, 5 (iv) Important
Ex 14.3, 5 (v)
Ex 14.3, 5 (vi) You are here
Ex 14.3, 5 (vii) Important
Transcript
Ex 14.3, 5 Factorise the expressions and divide them as directed. (vi) 12xy(9๐ฅ^2 โ 16๐ฆ^2) รท 4xy(3x + 4y) We first factorise 12xy (ใ9๐ฅใ^2โ16๐ฆ^2) = 12xy [(ใ3๐ฅใ^2) โ (ใ4๐ฆใ^2)] We first factorise 12xy (ใ9๐ฅใ^2โ16๐ฆ^2) = 12xy [(ใ3๐ฅใ^2) โ (ใ4๐ฆใ^2)] Using ๐^2 โ ๐^2 = (a + b) (a โ b) Here ๐= 3x and b = 4y Using ๐^2 โ ๐^2 = (a + b) (a โ b) Here ๐= 3x and b = 4y = (12๐ฅ๐ฆ (9๐ฅ^2 โ 16๐ฆ^2))/(4๐ฅ๐ฆ (3๐ฅ + 4๐ฆ)) = (12๐ฅ๐ฆ (3๐ฅ + 4๐ฆ) (3๐ฅ โ 4๐ฆ))/(4๐ฅ๐ฆ (3๐ฅ + 4๐ฆ)) = 12/4 ร ๐ฅ๐ฆ/๐ฅ๐ฆ ร ((3๐ฅ + 4๐ฆ))/((3๐ฅ + 4๐ฆ)) ร (3x โ 4y) = 3 (3x โ 4y)
