Ex 14.3, 2 (iv) - Chapter 14 Class 8 Factorisation

Last updated at March 23, 2023 by Teachoo

Ex 14.3, 2 (iv) - Divide (x^3 + 2x^2 + 3x) ÷ 2x - Polynomial by Mono

Ex 14.3, 2 (iv) - Chapter 14 Class 8 Factorisation - Part 2

Ex 14.3, 2 (iv) - Chapter 14 Class 8 Factorisation - Part 3

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Transcript

Ex 14.3, 2 (Method 1) Divide the given polynomial by the given monomial. (iv) (𝑥^3 + 2𝑥^2 + 3𝑥) ÷ 2𝑥 𝑥^3 + 2𝑥^2 + 3𝑥 = (𝑥^2 × 𝑥) + (2𝑥 × 𝑥) + (3 × 𝑥) Taking 𝑥 common, = 𝑥 (𝑥^2 + 2𝑥 + 3) Dividing (𝑥^3 " + " 2𝑥^2 " + " 3𝑥)/2𝑥 = (𝑥 (𝑥^2 + 2𝑥 + 3))/2𝑥 = 𝑥/𝑥 × (𝑥^2+ 2𝑥 + 3)/2 = (𝑥^2+ 2𝑥 + 3)/2 = 𝟏/𝟐 (𝒙^𝟐 + 2𝒙 + 3) Ex 14.3, 2 (Method 2) Divide the given polynomial by the given monomial. (iv) (𝑥^3 + 2𝑥^2 + 3𝑥) ÷ 2𝑥 (𝑥^2+ 2𝑥 + 3)/2𝑥 = 𝑥^3/2𝑥 + (2𝑥^2)/2𝑥 + 3𝑥/2𝑥 = (1/2×𝑥^3/𝑥) + (2/2×𝑥^2/𝑥) + (3/2×𝑥/𝑥) = (1/2×𝑥^2 ) + (1×𝑥) + (3/2×1) = 1/2 𝑥^2+ 𝑥 + 3/2 = (𝑥^2+ 2𝑥 + 3 )/2 = 𝟏/𝟐 (𝒙^𝟐 + 2𝒙 + 3)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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