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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 12.3, 2 (Method 1) Divide the given polynomial by the given monomial. (iv) (๐‘ฅ^3 + 2๐‘ฅ^2 + 3๐‘ฅ) รท 2๐‘ฅ๐‘ฅ^3 + 2๐‘ฅ^2 + 3๐‘ฅ = (๐‘ฅ^2 ร— ๐‘ฅ) + (2๐‘ฅ ร— ๐‘ฅ) + (3 ร— ๐‘ฅ) Taking ๐‘ฅ common, = ๐‘ฅ (๐‘ฅ^2 + 2๐‘ฅ + 3) Dividing (๐‘ฅ^3 " + " 2๐‘ฅ^2 " + " 3๐‘ฅ)/2๐‘ฅ = (๐‘ฅ (๐‘ฅ^2 + 2๐‘ฅ + 3))/2๐‘ฅ = ๐‘ฅ/๐‘ฅ ร— (๐‘ฅ^2+ 2๐‘ฅ + 3)/2 = (๐‘ฅ^2+ 2๐‘ฅ + 3)/2 = ๐Ÿ/๐Ÿ (๐’™^๐Ÿ + 2๐’™ + 3) Ex 12.3, 2 (Method 2) Divide the given polynomial by the given monomial. (iv) (๐‘ฅ^3 + 2๐‘ฅ^2 + 3๐‘ฅ) รท 2๐‘ฅ (๐‘ฅ^2+ 2๐‘ฅ + 3)/2๐‘ฅ = ๐‘ฅ^3/2๐‘ฅ + (2๐‘ฅ^2)/2๐‘ฅ + 3๐‘ฅ/2๐‘ฅ = (๐Ÿ/๐Ÿร—๐’™^๐Ÿ‘/๐’™) + (๐Ÿ/๐Ÿร—๐’™^๐Ÿ/๐’™) + (๐Ÿ‘/๐Ÿร—๐’™/๐’™) = (1/2ร—๐‘ฅ^2 ) + (1ร—๐‘ฅ) + (3/2ร—1) = 1/2 ๐‘ฅ^2+ ๐‘ฅ + 3/2 = (๐‘ฅ^2+ 2๐‘ฅ + 3 )/2 = ๐Ÿ/๐Ÿ (๐’™^๐Ÿ + 2๐’™ + 3)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.