Ex 14.3, 3 Work out the following divisions. (iv) 9𝑥^2 𝑦^2(3z – 24) ÷ 27xy(z – 8) We first factorise 〖9𝑥〗^2 𝑦^2 (3z − 24) = 〖9𝑥〗^2 𝑦^2 × [3z − (3 × 8)] Taking 3 common, = 〖9𝑥〗^2 𝑦^2 × 3 (z − 8) = 27 𝑥^2 𝑦^2 (z − 8) Dividing, (9𝑥^2 𝑦^2 (3𝑧 − 24))/(27𝑥𝑦 (𝑧 − 8)) = (27𝑥^2 𝑦^2 (𝑧 − 8))/(27𝑥𝑦 (𝑧 − 8)) = 27/27 × 𝑥^2/𝑥 × 𝑦^2/𝑦 × ((𝑧 − 8))/((𝑧 − 8)) = 1 × x × y × 1 = xy (𝐴𝑠 𝑎^𝑚/𝑎^𝑛 =𝑎^(𝑚 − n) )

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.

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