Ex 14.3, 3 (iv) - Work out the division 9x2y2(3z - 24) ÷ 27xy(z - 8)

Ex 14.3, 3 (iv) - Chapter 14 Class 8 Factorisation - Part 2

  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Ex 14.3, 3 Work out the following divisions. (iv) 9๐‘ฅ^2 ๐‘ฆ^2(3z โ€“ 24) รท 27xy(z โ€“ 8) We first factorise ใ€–9๐‘ฅใ€—^2 ๐‘ฆ^2 (3z โˆ’ 24) = ใ€–9๐‘ฅใ€—^2 ๐‘ฆ^2 ร— [3z โˆ’ (3 ร— 8)] Taking 3 common, = ใ€–9๐‘ฅใ€—^2 ๐‘ฆ^2 ร— 3 (z โˆ’ 8) = 27 ๐‘ฅ^2 ๐‘ฆ^2 (z โˆ’ 8) Dividing, (9๐‘ฅ^2 ๐‘ฆ^2 (3๐‘ง โˆ’ 24))/(27๐‘ฅ๐‘ฆ (๐‘ง โˆ’ 8)) = (27๐‘ฅ^2 ๐‘ฆ^2 (๐‘ง โˆ’ 8))/(27๐‘ฅ๐‘ฆ (๐‘ง โˆ’ 8)) = 27/27 ร— ๐‘ฅ^2/๐‘ฅ ร— ๐‘ฆ^2/๐‘ฆ ร— ((๐‘ง โˆ’ 8))/((๐‘ง โˆ’ 8)) = 1 ร— x ร— y ร— 1 = xy (๐ด๐‘  ๐‘Ž^๐‘š/๐‘Ž^๐‘› =๐‘Ž^(๐‘š โˆ’ n) )

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.