Ex 14.3, 3 (iv) - Chapter 14 Class 8 Factorisation
Last updated at Dec. 26, 2018 by Teachoo
Transcript
Ex 14.3, 3 Work out the following divisions. (iv) 9π₯^2 π¦^2(3z β 24) Γ· 27xy(z β 8) We first factorise γ9π₯γ^2 π¦^2 (3z β 24) = γ9π₯γ^2 π¦^2 Γ [3z β (3 Γ 8)] Taking 3 common, = γ9π₯γ^2 π¦^2 Γ 3 (z β 8) = 27 π₯^2 π¦^2 (z β 8) Dividing, (9π₯^2 π¦^2 (3π§ β 24))/(27π₯π¦ (π§ β 8)) = (27π₯^2 π¦^2 (π§ β 8))/(27π₯π¦ (π§ β 8)) = 27/27 Γ π₯^2/π₯ Γ π¦^2/π¦ Γ ((π§ β 8))/((π§ β 8)) = 1 Γ x Γ y Γ 1 = xy (π΄π π^π/π^π =π^(π β n) )
Ex 14.3
Ex 14.3, 1 (i)
Ex 14.3, 1 (ii)
Ex 14.3, 1 (iii)
Ex 14.3, 1 (iv)
Ex 14.3, 1 (v) Important
Ex 14.3, 2 (i)
Ex 14.3, 2 (ii) Important
Ex 14.3, 2 (iii) Important
Ex 14.3, 2 (iv)
Ex 14.3, 2 (v)
Ex 14.3, 3 (i)
Ex 14.3, 3 (ii)
Ex 14.3, 3 (iii) Important
Ex 14.3, 3 (iv) You are here
Ex 14.3, 3 (v) Important
Ex 14.3, 4 (i)
Ex 14.3, 4 (ii)
Ex 14.3, 4 (iii) Important
Ex 14.3, 4 (iv)
Ex 14.3, 4 (v)
Ex 14.3, 5 (i)
Ex 14.3, 5 (ii) Important
Ex 14.3, 5 (iii) Important
Ex 14.3, 5 (iv) Important
Ex 14.3, 5 (v)
Ex 14.3, 5 (vi)
Ex 14.3, 5 (vii) Important
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.