Ex 14.3

Chapter 14 Class 8 Factorisation
Serial order wise

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Ex 14.3, 2 (Method 1) Divide the given polynomial by the given monomial. (iii) 8 (๐ฅ^3 ๐ฆ^2 ๐ง^2 +๐ฅ^2 ๐ฆ^3 ๐ง^2 + ๐ฅ^2 ๐ฆ^2 ๐ง^3) รท 4๐ฅ^2 ๐ฆ^2 ๐ง^2 8 (๐ฅ^3 ๐ฆ^2 ๐ง^2 +๐ฅ^2 ๐ฆ^3 ๐ง^2 + ๐ฅ^2 ๐ฆ^2 ๐ง^3) = 8 (๐ฅร๐ฅ^2 ๐ฆ^2 ๐ง^2) + (๐ฆ ร ๐ฅ^2 ๐ฆ^2 ๐ง^2) + (z ร ๐ฅ^2 ๐ฆ^2 ๐ง^2) Taking ๐ฅ^2 ๐ฆ^2 ๐ง^2 common = 8๐ฅ^2 ๐ฆ^2 ๐ง^2 (๐ฅ + y +z) Dividing (8 (๐ฅ^3 ๐ฆ^2 ๐ง^2 + ๐ฅ^2 ๐ฆ^3 ๐ง^2 + ๐ฅ^2 ๐ฆ^2 ๐ง^3))/(4๐ฅ^2 ๐ฆ^2 ๐ง^2 ) = (8ใ ๐ฅใ^2 ๐ฆ^2 ๐ง^2 (๐ฅ + ๐ฆ + ๐ง))/(4๐ฅ^2 ๐ฆ^2 ๐ง^2 ) = 8/4 ร (๐ฅ^2 ๐ฆ^2 ๐ง^2)/(๐ฅ^2 ๐ฆ^2 ๐ง^2 ) ร (๐ฅ + y + z) = 2 ร (๐ฅ + y + z) = 2 (๐ + y + z) Ex 14.3, 2 (Method 2) Divide the given polynomial by the given monomial. (iii) 8 (๐ฅ^3 ๐ฆ^2 ๐ง^2 +๐ฅ^2 ๐ฆ^3 ๐ง^2 + ๐ฅ^2 ๐ฆ^2 ๐ง^3) รท 4๐ฅ^2 ๐ฆ^2 ๐ง^2 8 (๐ฅร๐ฅ^2 ๐ฆ^2 ๐ง^2) + (๐ฆ ร ๐ฅ^2 ๐ฆ^2 ๐ง^2) + (z ร ๐ฅ^2 ๐ฆ^2 ๐ง^2) = (8 (๐ฅ^3 ๐ฆ^2 ๐ง^2 + ๐ฅ^2 ๐ฆ^3 ๐ง^2 + ๐ฅ^2 ๐ฆ^2 ๐ง^3))/(4๐ฅ^2 ๐ฆ^2 ๐ง^2 ) = (8๐ฅ^3 ๐ฆ^2 ๐ง^2)/(4๐ฅ^2 ๐ฆ^2 ๐ง^2 ) + (8๐ฅ^2 ๐ฆ^3 ๐ง^2)/(4๐ฅ^2 ๐ฆ^2 ๐ง^2 ) + (8๐ฅ^2 ๐ฆ^2 ๐ง^3)/(4๐ฅ^2 ๐ฆ^2 ๐ง^2 ) = 2๐ฅ + 2y + 2z Taking (x + y + z) common = 2 (๐ + y + z)

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#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.