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Ex 14.3, 2 (iii) - Divide 8(x^3y^2z^2 + x^2y^3z^2 + x^2y^2z^3) รท 4x^2

Ex 14.3, 2 (iii) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.3, 2 (iii) - Chapter 14 Class 8 Factorisation - Part 3

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Ex 14.3, 2 (Method 1) Divide the given polynomial by the given monomial. (iii) 8 (๐‘ฅ^3 ๐‘ฆ^2 ๐‘ง^2 +๐‘ฅ^2 ๐‘ฆ^3 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^3) รท 4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 8 (๐‘ฅ^3 ๐‘ฆ^2 ๐‘ง^2 +๐‘ฅ^2 ๐‘ฆ^3 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^3) = 8 (๐‘ฅร—๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2) + (๐‘ฆ ร— ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2) + (z ร— ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2) Taking ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 common = 8๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 (๐‘ฅ + y +z) Dividing (8 (๐‘ฅ^3 ๐‘ฆ^2 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^3 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^3))/(4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) = (8ใ€– ๐‘ฅใ€—^2 ๐‘ฆ^2 ๐‘ง^2 (๐‘ฅ + ๐‘ฆ + ๐‘ง))/(4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) = 8/4 ร— (๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2)/(๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) ร— (๐‘ฅ + y + z) = 2 ร— (๐‘ฅ + y + z) = 2 (๐’™ + y + z) Ex 14.3, 2 (Method 2) Divide the given polynomial by the given monomial. (iii) 8 (๐‘ฅ^3 ๐‘ฆ^2 ๐‘ง^2 +๐‘ฅ^2 ๐‘ฆ^3 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^3) รท 4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 8 (๐‘ฅร—๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2) + (๐‘ฆ ร— ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2) + (z ร— ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2) = (8 (๐‘ฅ^3 ๐‘ฆ^2 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^3 ๐‘ง^2 + ๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^3))/(4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) = (8๐‘ฅ^3 ๐‘ฆ^2 ๐‘ง^2)/(4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) + (8๐‘ฅ^2 ๐‘ฆ^3 ๐‘ง^2)/(4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) + (8๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^3)/(4๐‘ฅ^2 ๐‘ฆ^2 ๐‘ง^2 ) = 2๐‘ฅ + 2y + 2z Taking (x + y + z) common = 2 (๐’™ + y + z)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.