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Ex 12.3, 5 (i) - Chapter 12 Class 8 Factorisation
Last updated at Aug. 8, 2023 by Teachoo
Ex 12.3
Ex 12.3, 1 (i)
Ex 12.3, 1 (ii) Important
Ex 12.3, 1 (iii)
Ex 12.3, 1 (iv) Important
Ex 12.3, 1 (v)
Ex 12.3, 2 (i)
Ex 12.3, 2 (ii) Important
Ex 12.3, 2 (iii) Important
Ex 12.3, 2 (iv)
Ex 12.3, 2 (v) Important
Ex 12.3, 3 (i)
Ex 12.3, 3 (ii)
Ex 12.3, 3 (iii) Important
Ex 12.3, 3 (iv)
Ex 12.3, 3 (v) Important
Ex 12.3, 4 (i)
Ex 12.3, 4 (ii) Important
Ex 12.3, 4 (iii)
Ex 12.3, 4 (iv)
Ex 12.3, 4 (v) Important
Ex 12.3, 5 (i) You are here
Ex 12.3, 5 (ii) Important
Ex 12.3, 5 (iii)
Ex 12.3, 5 (iv) Important
Ex 12.3, 5 (v)
Ex 12.3, 5 (vi)
Ex 12.3, 5 (vii) Important
Chapter 12 Class 8 Factorisation
Serial order wise
Transcript
Ex 12.3, 5 Factorise the expressions and divide them as directed. (i) (๐ฆ^2 + 7y + 10) รท (y + 5)We first factorise ๐ฆ^2+7๐ฆ+10 By middle term splitting, ๐^๐ + 7y +10 = ๐ฆ^2 + 2y + 5y + 10 = (๐ฆ^2+2๐ฆ) + (5๐ฆ+10) = y (y + 2) + 5 (y + 2) Taking (y + 2) common, = (y + 2) (y + 5) Splitting the middle term We need to find two numbers whose Sum = 7 Product = 10 So, we write 7y = 2y + 5y Now, Dividing (๐ฆ^2+7๐ฆ+10)รท(๐ฆ+5) = (๐ฆ^2 + 7๐ฆ + 10)/((๐ฆ + 5)) = ((๐ + ๐) (๐ + ๐))/((๐ + ๐)) = (๐ฆ + 2) ร ((๐ฆ + 5))/((๐ฆ + 5)) = (๐ + 2)
