Ex 12.3, 3 (iii) - Chapter 12 Class 8 Factorisation

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Ex 12.3, 3 Work out the following divisions. (iii) 10y(6y + 21) ÷ 5(2y + 7)We first factorise 10y (6y + 21) = 10y [(3 × 2) y + (3 × 7)] Taking 3 common, = 10y × 3 (2y + 7) Dividing, (10𝑦 (6𝑦 + 21) )/(5 (2𝑦 +7)) = (10𝑦 × 3(2𝑦 + 7))/(5 × (2𝑦 + 7)) = 3 × 10/5 × y × ((2𝑦 + 7))/((2𝑦 + 7)) = 3 × 2 × y × 1 = 6y

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo