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Ex 14.3, 3 (iii) - Chapter 14 Class 8 Factorisation
Last updated at March 23, 2023 by Teachoo
Ex 14.3
Ex 14.3, 1 (i)
Ex 14.3, 1 (ii) Important
Ex 14.3, 1 (iii)
Ex 14.3, 1 (iv) Important
Ex 14.3, 1 (v)
Ex 14.3, 2 (i)
Ex 14.3, 2 (ii) Important
Ex 14.3, 2 (iii) Important
Ex 14.3, 2 (iv)
Ex 14.3, 2 (v) Important
Ex 14.3, 3 (i)
Ex 14.3, 3 (ii)
Ex 14.3, 3 (iii) Important You are here
Ex 14.3, 3 (iv)
Ex 14.3, 3 (v) Important
Ex 14.3, 4 (i)
Ex 14.3, 4 (ii) Important
Ex 14.3, 4 (iii)
Ex 14.3, 4 (iv)
Ex 14.3, 4 (v) Important
Ex 14.3, 5 (i)
Ex 14.3, 5 (ii) Important
Ex 14.3, 5 (iii)
Ex 14.3, 5 (iv) Important
Ex 14.3, 5 (v)
Ex 14.3, 5 (vi)
Ex 14.3, 5 (vii) Important
Transcript
Ex 14.3, 3 Work out the following divisions. (iii) 10y(6y + 21) ÷ 5(2y + 7) We first factorise 10y (6y + 21) = 10y [(3 × 2) y + (3 × 7)] Taking 3 common, = 10y × 3 (2y + 7) Dividing, (10𝑦 (6𝑦 + 21) )/(5 (2𝑦 +7)) = (10𝑦 × 3(2𝑦 + 7))/(5 × (2𝑦 + 7)) = 3 × 10/5 × y × ((2𝑦 + 7))/((2𝑦 + 7)) = 3 × 2 × y × 1 = 6y
