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Ex 14.3, 3 (iii) - Work out the division 10y(6y + 21) ÷ 5(2y + 7)

Ex 14.3, 3 (iii) - Chapter 14 Class 8 Factorisation - Part 2

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Transcript

Ex 14.3, 3 Work out the following divisions. (iii) 10y(6y + 21) ÷ 5(2y + 7) We first factorise 10y (6y + 21) = 10y [(3 × 2) y + (3 × 7)] Taking 3 common, = 10y × 3 (2y + 7) Dividing, (10𝑦 (6𝑦 + 21) )/(5 (2𝑦 +7)) = (10𝑦 × 3(2𝑦 + 7))/(5 × (2𝑦 + 7)) = 3 × 10/5 × y × ((2𝑦 + 7))/((2𝑦 + 7)) = 3 × 2 × y × 1 = 6y

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.