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Ex 12.3, 3 Work out the following divisions. (v) 96 abc (3a – 12) (5b – 30) ÷ 144 (a – 4) (b – 6)We first factorise 96 abc (3a − 12) (5b − 30) = 96 abc (3a − (3 × 4)) (5b − 30) Taking 3 common, = 96 abc × 3 (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 5 × 6) Taking 5 common, = 288 abc (a − 4) × 5 (b − 6) = 288 × 5 abc (a − 4) (b − 6) = 1440 abc (a − 4) (b − 6) Dividing, (96 𝑎𝑏𝑐 (3𝑎 −12) (5𝑏 − 30))/(144 (𝑎 − 4) (𝑏 − 6)) = (1440 𝑎𝑏𝑐 (𝑎 − 4) (𝑏 − 6))/(144 (𝑎 − 4) (𝑏 − 6)) = 1440/144 × abc × ((𝑎 − 4))/((𝑎 − 4)) × ((𝑏 − 6))/((𝑏 − 6)) = 10 × abc × 1 × 1 = 10 abc

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.