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Ex 12.3, 3 (v) - Chapter 12 Class 8 Factorisation
Last updated at Aug. 8, 2023 by Teachoo
Ex 12.3
Ex 12.3, 1 (i)
Ex 12.3, 1 (ii) Important
Ex 12.3, 1 (iii)
Ex 12.3, 1 (iv) Important
Ex 12.3, 1 (v)
Ex 12.3, 2 (i)
Ex 12.3, 2 (ii) Important
Ex 12.3, 2 (iii) Important
Ex 12.3, 2 (iv)
Ex 12.3, 2 (v) Important
Ex 12.3, 3 (i)
Ex 12.3, 3 (ii)
Ex 12.3, 3 (iii) Important
Ex 12.3, 3 (iv)
Ex 12.3, 3 (v) Important You are here
Ex 12.3, 4 (i)
Ex 12.3, 4 (ii) Important
Ex 12.3, 4 (iii)
Ex 12.3, 4 (iv)
Ex 12.3, 4 (v) Important
Ex 12.3, 5 (i)
Ex 12.3, 5 (ii) Important
Ex 12.3, 5 (iii)
Ex 12.3, 5 (iv) Important
Ex 12.3, 5 (v)
Ex 12.3, 5 (vi)
Ex 12.3, 5 (vii) Important
Chapter 12 Class 8 Factorisation
Serial order wise
Transcript
Ex 12.3, 3 Work out the following divisions. (v) 96 abc (3a – 12) (5b – 30) ÷ 144 (a – 4) (b – 6)We first factorise 96 abc (3a − 12) (5b − 30) = 96 abc (3a − (3 × 4)) (5b − 30) Taking 3 common, = 96 abc × 3 (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 5 × 6) Taking 5 common, = 288 abc (a − 4) × 5 (b − 6) = 288 × 5 abc (a − 4) (b − 6) = 1440 abc (a − 4) (b − 6) Dividing, (96 𝑎𝑏𝑐 (3𝑎 −12) (5𝑏 − 30))/(144 (𝑎 − 4) (𝑏 − 6)) = (1440 𝑎𝑏𝑐 (𝑎 − 4) (𝑏 − 6))/(144 (𝑎 − 4) (𝑏 − 6)) = 1440/144 × abc × ((𝑎 − 4))/((𝑎 − 4)) × ((𝑏 − 6))/((𝑏 − 6)) = 10 × abc × 1 × 1 = 10 abc
