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  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Ex 14.3, 3 Work out the following divisions. (v) 96 abc (3a – 12) (5b – 30) ÷ 144 (a – 4) (b – 6) We first factorise 96 abc (3a − 12) (5b − 30) = 96 abc (3a − (3 × 4)) (5b − 30) Taking 3 common, = 96 abc × 3 (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 30) = 288 abc (a − 4) (5b − 5 × 6) Taking 5 common, = 288 abc (a − 4) × 5 (b − 6) = 288 × 5 abc (a − 4) (b − 6) = 1440 abc (a − 4) (b − 6) Dividing, (96 𝑎𝑏𝑐 (3𝑎 −12) (5𝑏 − 30))/(144 (𝑎 − 4) (𝑏 − 6)) = (1440 𝑎𝑏𝑐 (𝑎 − 4) (𝑏 − 6))/(144 (𝑎 − 4) (𝑏 − 6)) = 1440/144 × abc × ((𝑎 − 4))/((𝑎 − 4)) × ((𝑏 − 6))/((𝑏 − 6)) = 10 × abc × 1 × 1 = 10 abc

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.