Ex 6.2, 1 Class 12 - Show that f(x) = 3x + 17 is strictly increasing

Ex 6.2, 1 - Chapter 6 Class 12 Application of Derivatives - Part 2

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Ex 6.2, 1 (Method 1) Show that the function given by f (š‘„) = 3š‘„ + 17 is strictly increasing on R. f(š‘„) = 3š‘„ + 17 Finding f’(š’™) f’(š‘„) = 3 Since f’(š’™) > 0 Hence, f is strictly increasing on R Ex 6.2, 1 (Method 2) Show that the function given by f (x) = 3x + 17 is strictly increasing on R. Let š‘„1 and š‘„2 be real numbers Such that š’™šŸ < š’™2 Multiplying both sides by 3 3š‘„1 < 3 š‘„2 Adding both sides by 17 3š‘„1 + 17 < 3š‘„2 + 17 f (š’™šŸ) < f ( š’™2) Hence, when x1 < x2 , f(x1) < f(x2) Thus, f(x) is strictly increasing on R.

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