# Misc 13

Last updated at March 11, 2017 by Teachoo

Last updated at March 11, 2017 by Teachoo

Transcript

Misc 13 Assume that the chances of a patient having a heart attack is 40%. It is also assumed that a meditation and yoga course reduce the risk of heart attack by 30% and prescription of certain drug reduces its chances by 25%. At a time a patient can choose any one of the two options with equal probabilities. It is given that after going through one of the two options the patient selected at random suffers a heart attack. Find the probability that the patient followed a course of meditation and yoga? Normal risk of heart attack is 40%. If we do meditation and yoga, it reduces risk by 30% i.e. risk becomes 40% 70% = 28% Let A : Person has heart attack E1 : Person is treated with meditation & yoga E2 : Person is treated with drug Given, P(A) = 40 % = 0.40 Also, given that meditation & yoga and drug has equal probabilities P(E1) = 1 2 , P(E2) = 1 2 We have to find that if a person selected has an heart attack, what is the probability that the person followed meditation & yoga. i.e. P(E1|A) P(E1|A) = 1 . ( | 1 ) 1 . ( | 1 )+ 2 . ( | 2 )

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Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.