Example 32
Last updated at March 11, 2017 by Teachoo
Transcript
Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg. Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx 𝒒𝒏−𝒙 𝒑𝒙 n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10100 = 110 q = 1 – p = 1 – 110 = 910 Hence, P(X = x) = 10Cx 𝟏𝟏𝟎𝒙 𝟗𝟏𝟎𝟏𝟎 − 𝒙 We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 – P(getting 0 defective eggs) = 1 – P(X = 0) = 1 – 10C0 1100 91010 −0 = 1 – 1 × 1 × 91010 = 1 – 91010
Chapter 13 Class 12 Probability
Example 7
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Example 6 Important
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Example 31 Important
Example 32 Important You are here
Ex 13.5, 4 Important
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Example 35 Important
Example 36 Important
Misc 6 Important
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Class 12
Important Question for exams Class 12
- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability
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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .