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Chapter 13 Class 12 Probability

Ex 13.3, 10 - Suppose a girl throws die. If she gets a 5 or 6

Ex 13.3, 10 - Chapter 13 Class 12 Probability - Part 2
Ex 13.3, 10 - Chapter 13 Class 12 Probability - Part 3

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Transcript

Ex 13.3, 10 Suppose a girl throws a die. If she gets a 5 or 6, she tosses a coin three times and notes the number of heads. If she gets 1, 2, 3 or 4, she tosses a coin once and notes whether a head or tail is obtained. If she obtained exactly one head, what is the probability that she threw 1, 2, 3 or 4 with the die?Let A : 1, 2, 3, 4 appear on the die B : 5, 6 appear on the die C : exactly one head is obtained We need to find the Probability that if exactly one head is obtained on the toss of a coin, she threw 1, 2, 3 or 4 with the die i.e. P(A|C) P(A|C) = (𝑃(𝐴) ." " 𝑃(𝐢|𝐴))/(𝑃(𝐴) . 𝑃(𝐢|𝐴) + 𝑃(𝐡) . 𝑃(𝐢|𝐡) ) "P(A)" = Probability that 1, 2, 3 or 4 appear on the die = 4/6 = 𝟐/πŸ‘ "P(C|A)" = Probability that exactly one head is obtained, if 1, 2, 3 or 4 appear on the die = 𝟏/𝟐 "P(B)" = Probability that 5 or 6 appear on the die = 2/6 = 𝟏/πŸ‘ "P(C|B)" = Probability that exactly one head is obtained, if 5 or 6 appear on the die = πŸ‘/πŸ– Puttinag values in formula, P(A"|"C) = (2/3 Γ— 1/2)/( 2/3 Γ— 1/2 + 1/3 Γ— 3/8 ) = (1/3 Γ— 1/2 Γ— 2)/( 1/3 Γ— 1/2 [2 + 3/4 ] ) = 2/( 2 + 3/4 ) = 2/(11/4) = πŸ–/𝟏𝟏 Therefore, required probability is 8/11

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