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Chapter 4 Class 12 Determinants
Example 14 Important Deleted for CBSE Board 2023 Exams
Example 15 Important Deleted for CBSE Board 2023 Exams
Example 16 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 7 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 8 (i) Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 11 (i) Deleted for CBSE Board 2023 Exams
Ex 4.2, 12 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 13 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 14 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 15 (MCQ) Important Deleted for CBSE Board 2023 Exams
Example 18 Important
Ex 4.3, 2 Important
Ex 4.3, 3 (i) Important
Example 24 Important
Example 26 Important
Ex 4.5, 10 Important
Ex 4.5, 15 Important
Ex 4.5, 18 (MCQ) Important
Ex 4.6, 13 Important
Ex 4.6, 15 Important
Ex 4.6, 16 Important
Example 32 Important Deleted for CBSE Board 2023 Exams
Example 34 Important Deleted for CBSE Board 2023 Exams
Misc. 2 Important Deleted for CBSE Board 2023 Exams
Misc 11 Important Deleted for CBSE Board 2023 Exams
Misc. 15 Important Deleted for CBSE Board 2023 Exams
Misc. 16 Important
Misc 19 (MCQ) Important
Chapter 4 Class 12 Determinants
Last updated at March 16, 2023 by Teachoo
Ex 4.1, 7 Find values of x, if (i) |■8(2&[email protected]&1)| = |■8(2x&[email protected]&x)|Calculating |■8(2&[email protected]&1)| = 2(1) – 5(4) = 2 – 20 = – 18 Calculating |■8(2x&[email protected]&x)| = 2x(x) – 6 × 4 = 2x2 – 24 Now |■8(2&[email protected]&1)| = |■8(2x&[email protected]&x)| Putting values −18 = 2x2 – 24 2x2 – 24 = −18 2x2 = −18 + 24 2x2 = 6 x2 = 6/2 x2 = 3 x = ± √𝟑 Hence, value of x is ± √3