Misc 11 - In a game, a man wins a rupee for a six and loses - Basic Probability

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  1. Class 12
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Misc 11 In a game, a man wins a rupee for a six and loses a rupee for any other number when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a six. Find the expected value of the amount he wins / loses. 1st throw : He gets a six P(win) = 1 6 Amount won = 1 2nd throw : He does not get 6 in 1st throw , He gets six in 2nd throw So, P(win) = 5 6 1 6 = 5 36 Amount won = 1 + 1 = 0 3nd throw : He does not get 6 in 1st throw , He does not get 6 in 2nd throw ,He gets six in 3rd throw So, P(win) = 5 6 5 6 1 6 = 25 216 Amount won = 1 1 + 1 = 1 Expected Value = Amount won Probability for all three throws = (1 ) + (0 ) + ( 1 ) = 1 6 + 0 25 216 = 1 6 25 216 = 36 25 216 =

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.