Example 39 - Chapter 1 Class 12 Relation and Functions
Last updated at June 29, 2018 by Teachoo
Transcript
Example 39 Show that – a is the inverse of a for the addition operation ‘+’ on R and 1a is the inverse of a ≠ 0 for the multiplication operation ‘×’ on R. Addition An element a in R is invertible if, there is an element b in R such that , a * b = e = b * a Here, b is the inverse of a Here, e = 0 for addition So, a * b = e = b * a a + b = 0 = b + a ⇒ b = –a Since a + (– a) = 0 = (– a) + a = 0, So, –a is the inverse of a for addition. Multiplication An element a in R is invertible if, there is an element b in R such that , a * b = e = b * a Here, b is the inverse of a Here, e = 1 for multiplication So, a * b = e = b * a a × b = 1 = b × a ⇒ b = 1𝑎 Since a × 1𝑎 = 1 = 1𝑎 × a So, 𝟏𝒂 is the inverse of a for addition.
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Example 39 You are here
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Chapter 1 Class 12 Relation and Functions
Serial order wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.