Example 7 - Find the value of k, if x – 1 is a factor - Examples - Examples

part 2 - Example 7 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

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Example 7 Find the value of k, if š‘„āˆ’1 is a factor of 4š‘„^3+3š‘„^2āˆ’4š‘„+š‘˜ Finding remainder when šŸ’š’™^šŸ‘+šŸ‘š’™^šŸāˆ’šŸ’š’™+š’Œ is divided by x – 1 Step 1: Putting Divisor = 0 x – 1 = 0 x = 1 Step 2: Let š‘(š‘„) = 4š‘„^3+3š‘„^2āˆ’4š‘„+š‘˜ Putting x = 1 š‘(šŸ) = 4怖(šŸ)怗^3+3怖(šŸ)怗^2āˆ’ 4(šŸ)+š‘˜ Dividend Divisor = 4+3āˆ’ 4+š‘˜ = šŸ‘+š’Œ Thus, Remainder = š‘(1) = 3+š‘˜ Step 3: Since š‘„ – 1 is a factor of 4š‘„^3+3š‘„^2āˆ’4š‘„+š‘˜ ∓ š’‘(šŸ) = 0 3+š‘˜ = 0 k = āˆ’3 Thus, k = āˆ’šŸ‘

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