Get live Maths 1-on-1 Classs - Class 6 to 12

Examples

Example 1 (i)

Example 1 (ii)

Example 1 (iii) Important

Example 2 (i)

Example 2 (ii)

Example 2 (iii)

Example 3 Important Deleted for CBSE Board 2023 Exams

Example 4

Example 5 Important

Example 6

Example 7 Important Deleted for CBSE Board 2023 Exams

Example 8

Example 9 Important

Example 10

Example 11 Important

Example 12 Important Deleted for CBSE Board 2023 Exams You are here

Example 13 Important

Example 14

Example 15 Important Deleted for CBSE Board 2023 Exams

Example 16 (i)

Example 16 (ii)

Example 17

Example 18 (i) Important Deleted for CBSE Board 2023 Exams

Example 18 (ii)

Example 19

Example 20

Example 21 Important Deleted for CBSE Board 2023 Exams

Example 22 (i)

Example 22 (ii)

Example 23 (i) Important Deleted for CBSE Board 2023 Exams

Example 23 (ii)

Example 24 Important Deleted for CBSE Board 2023 Exams

Example 25 Important

Last updated at March 28, 2023 by Teachoo

Example 12 Find the value of k, if π₯β1 is a factor of 4π₯^3+3π₯^2β4π₯+π Finding remainder when ππ^π+ππ^πβππ+π is divided by x β 1 Step 1: Putting Divisor = 0 x β 1 = 0 x = 1 Step 2: Let π(π₯) = 4π₯^3+3π₯^2β4π₯+π Putting x = 1 π(π) = 4γ(π)γ^3+3γ(π)γ^2β 4(π)+π Dividend Divisor = 4+3β 4+π = π+π Thus, Remainder = π(1) = 3+π Step 3: Since π₯ β 1 is a factor of 4π₯^3+3π₯^2β4π₯+π β΄ π(π) = 0 3+π = 0 k = β3 Thus, k = βπ