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Last updated at Aug. 25, 2021 by Teachoo

Transcript

Example 23 Evaluate each of the following using suitable identities: (ii) (999) 3 We write 999 = 1000 – 1 (999) 3 = (1000 – 1) 3 Using (a – b)3 = a3 – b3 – 3ab(a – b) Where a = 1000 & b = 1 = (1000) 3 – (1) 3 – 3(1000)(1)(1000 – 1) = 1000000000 – 1 – 3(1000)(1)(999) = 1000000000 – 1 – 2997000 = 997002999

Examples

Example 1 (i)

Example 1 (ii)

Example 1 (iii) Important

Example 2 (i)

Example 2 (ii)

Example 2 (iii)

Example 3 Important

Example 4

Example 5 Important

Example 6

Example 7 Important

Example 8 Deleted for CBSE Board 2022 Exams

Example 9 Important Deleted for CBSE Board 2022 Exams

Example 10

Example 11 Important

Example 12 Important

Example 13 Important

Example 14

Example 15 Important

Example 16 (i)

Example 16 (ii)

Example 17

Example 18 (i) Important

Example 18 (ii)

Example 19

Example 20

Example 21 Important

Example 22 (i)

Example 22 (ii)

Example 23 (i) Important

Example 23 (ii) You are here

Example 24 Important

Example 25 Important Deleted for CBSE Board 2022 Exams

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.