Example 14 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Example 14 Factorize y2 – 5y + 6 by using the Factor Theorem. Step 1: We check if y2 is multiplied by 1. y2 – 5y + 6. Step 2: Writing y2 – 5y + 6.= (y – a) (y – b) So, ab = Constant term = 6 We find factors of 6 6 = 6 × 1 6 = 3 × 2 So, factors of 6 are 1, 2 and 3. We take value of y as 1 , 2, 3, –1, –2, –3, and check value of y2 – 5y + 6. Hence, a = 2 , b = 3 Now, y2 – 5y + 6.= (y – a) (y – b) = (y – 2) (y – 3)
Examples
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Example 1 (ii)
Example 1 (iii) Important
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Example 3 Important
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Example 6
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Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
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Example 14 You are here
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Example 16 (i)
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Example 18 (i) Important
Example 18 (ii)
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Example 22 (i)
Example 22 (ii)
Example 23 (i) Important
Example 23 (ii)
Example 24 Important
Example 25 Important Deleted for CBSE Board 2022 Exams
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.