Example 14 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
Examples
Example 1 (i)
Example 1 (ii)
Example 1 (iii) Important
Example 2 (i)
Example 2 (ii)
Example 2 (iii)
Example 3 Important
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
Example 10
Example 11 Important
Example 12 Important
Example 13 Important
Example 14 You are here
Example 15 Important
Example 16 (i)
Example 16 (ii)
Example 17
Example 18 (i) Important
Example 18 (ii)
Example 19
Example 20
Example 21 Important
Example 22 (i)
Example 22 (ii)
Example 23 (i) Important
Example 23 (ii)
Example 24 Important
Example 25 Important Deleted for CBSE Board 2022 Exams
Transcript
Example 14 Factorize y2 – 5y + 6 by using the Factor Theorem. Step 1: We check if y2 is multiplied by 1. y2 – 5y + 6. Step 2: Writing y2 – 5y + 6.= (y – a) (y – b) So, ab = Constant term = 6 We find factors of 6 6 = 6 × 1 6 = 3 × 2 So, factors of 6 are 1, 2 and 3. We take value of y as 1 , 2, 3, –1, –2, –3, and check value of y2 – 5y + 6. Hence, a = 2 , b = 3 Now, y2 – 5y + 6.= (y – a) (y – b) = (y – 2) (y – 3)
