Example 9 - Chapter 2 Class 9 Polynomials

Last updated at July 20, 2026 by

Example 9 - Factorize y2 - 5y + 6 by using Factor Theorem - Examples

part 2 - Example 9 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

part 3 - Example 9 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

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Example 9 Factorize y2 – 5y + 6 by using the Factor Theorem. Step 1: We check if y2 is multiplied by 1. y2 – 5y + 6. Step 2: Writing y2 – 5y + 6.= (y – a) (y – b) So, ab = Constant term = 6 We find factors of 6 6 = 6 × 1 6 = 3 × 2 So, factors of 6 are 1, 2 and 3. We take value of y as 1 , 2, 3, –1, –2, –3, and check value of y2 – 5y + 6. Hence, a = 2 , b = 3 Now, y2 – 5y + 6.= (y – a) (y – b) = (y – 2) (y – 3)

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