Example 9 - Find remainder when x4 + x3 - 2x2 + x + 1 - Examples

  1. Chapter 2 Class 9 Polynomials
  2. Serial order wise
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Example 9 Find the remainder when x4 + x3 – 2x2 + x + 1 is divided by x – 1. Dividing x4 + x3 – 2x2 + x + 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = x4 + x3 – 2x2 + x + 1 Putting x = 1 p(1) = (1)4 + (1)3 – 2(1)2 + 1 + 1 = 1 + 1 – 2 + 1 + 1 = 2 So, Remainder = p(1) = 2

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