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Example 22 (ii) - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at March 22, 2023 by Teachoo
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Example 1 (ii)
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Example 22 (ii) You are here
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Transcript
Example 22 Write the following cubes in the expanded form: (ii) (5p – 3q)3 (5p – 3q)3 Using (x – y)3 = x3 – y3 – 3xy(x – y) Where x = 5p & y = 3q = (5p)3 – (3q)3 – 3(5p)(3q)(5p – 3q) = 125p3 – 27q3 – 3(5p)(3q)(5p) -3(5p)(3q) (– 3q) = 125p3 – 27q3 – 225p2q + 135pq2
