Example 19 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at Dec. 8, 2016 by
Transcript
Example 19 Write (3a + 4b + 5c)2 in expanded form. (3a + 4b + 5c)2 Using (x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx Putting x = 3a, y = 4b, z = 5c = (3a)2 + (4b)2 + (5c)2 + 2(3a)(4b) + 2(4b)(5c) + 2(5c)(3a) = 9a2 + 16b2 + 25c2 + (2 × 3 × 4) (a × b) + (2 × 4 × 5) (b × c) + (2 × 5 × 3) (a × c) = 9a2 + 16b2 + 25c2 + 24ab + 40bc + 30ac
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Example 1 (ii)
Example 1 (iii) Important
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Example 3 Important
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Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
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Example 16 (i)
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Example 18 (i) Important
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Example 19 You are here
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Example 22 (i)
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Example 23 (i) Important
Example 23 (ii)
Example 24 Important
Example 25 Important Deleted for CBSE Board 2022 Exams
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.
