Example 21 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at May 29, 2018 by Teachoo
Examples
Example 1 (i)
Example 1 (ii)
Example 1 (iii) Important
Example 2 (i)
Example 2 (ii)
Example 2 (iii)
Example 3 Important
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
Example 10
Example 11 Important
Example 12 Important
Example 13 Important
Example 14
Example 15 Important
Example 16 (i)
Example 16 (ii)
Example 17
Example 18 (i) Important
Example 18 (ii)
Example 19
Example 20
Example 21 Important You are here
Example 22 (i)
Example 22 (ii)
Example 23 (i) Important
Example 23 (ii)
Example 24 Important
Example 25 Important Deleted for CBSE Board 2022 Exams
Transcript
Example 21 Factorize 4x2 + y2 + z2 – 4xy – 2yz + 4xz. 4x2 + y2 + z2 – 4xy – 2yz + 4xz = 22 x2 + y2 + z2 – 4xy – 2yz + 4xz = (2x)2 + y2 + z2 – 4xy – 2yz + 4xz = (2x)2 + (–y)2 + z2 – 4xy – 2yz + 4xz = (2x)2 + (–y)2 + (z)2 + 2(2x)(–y) + 2(–y)(z) + 2(2x)(z) Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac where a = 2x, b= –y , c = z = (2x + (–y) + z)2 = (2x – y + z)2 = (2x – y + z)(2x – y + z)
