Example 16 - Chapter 2 Class 9 Polynomials
Last updated at Dec. 13, 2024 by Teachoo
Examples
Example 1 (i)
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Chapter 2 Class 9 Polynomials
Serial order wise
- Ex 2.1
- Ex 2.2
- Ex 2.3
- Ex 2.4
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Examples
- Remainder Theorem
Transcript
Example 16 Factorize 4x2 + y2 + z2 – 4xy – 2yz + 4xz. 4x2 + y2 + z2 – 4xy – 2yz + 4xz = 22 x2 + y2 + z2 – 4xy – 2yz + 4xz = (2x)2 + y2 + z2 – 4xy – 2yz + 4xz = (2x)2 + (–y)2 + z2 – 4xy – 2yz + 4xz = (2x)2 + (–y)2 + (z)2 + 2(2x)(–y) + 2(–y)(z) + 2(2x)(z) Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac where a = 2x, b= –y , c = z = (2x + (–y) + z)2 = (2x – y + z)2 = (2x – y + z)(2x – y + z)
