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Example 7 - Divide the polynomial 3x4 - 4x3 - 3x - 1 by x - 1 - Remainder Theoram

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Example 7 - Chapter 2 Class 9 Polynomials - Part 2
Example 7 - Chapter 2 Class 9 Polynomials - Part 3

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Transcript

Example 7 (Long division) Divide the polynomial 3x4 – 4x3 – 3x – 1 by x – 1. By long division Example 7 (Remainder theorem) Divide the polynomial 3x4 – 4x2 – 3x – 1 by x – 1. Dividing 3x4 – 4x2 – 3x – 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = 3x4 – 4x2 – 3x – 1 Putting x = 1 p(1) = 3(1)4 - 4(1)2 – 3(1) – 1 = 3(1) – 4(1) – 3 – 1 = 3 – 4 – 3 – 1 = –5 Thus, remainder = p(1) = –5

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.