Example 7
Last updated at March 16, 2017 by Teachoo
Transcript
Example 7 (Long division) Divide the polynomial 3x4 – 4x3 – 3x – 1 by x – 1. By long division Example 7 (Remainder theorem) Divide the polynomial 3x4 – 4x2 – 3x – 1 by x – 1. Dividing 3x4 – 4x2 – 3x – 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = 3x4 – 4x2 – 3x – 1 Putting x = 1 p(1) = 3(1)4 - 4(1)2 – 3(1) – 1 = 3(1) – 4(1) – 3 – 1 = 3 – 4 – 3 – 1 = –5 Thus, remainder = p(1) = –5
Examples
Example 1
Example 2
Example 3 Important
Example 4
Example 5
Example 6
Example 7 Important You are here
Example 8
Example 9
Example 10
Example 11
Example 12 Important
Example 13
Example 14
Example 15 Important
Example 16
Example 17
Example 18 Important
Example 19
Example 20
Example 21 Important
Example 22
Example 23 Important
Example 24 Important
Example 25
About the Author
CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .
