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Example 1 (iii) Important
Example 2 (i)
Example 2 (ii)
Example 2 (iii)
Example 3 Important
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Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
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Example 11 Important
Example 12 Important
Example 13 Important
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Example 16 (i)
Example 16 (ii)
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Example 18 (i) Important
Example 18 (ii)
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Example 22 (i)
Example 22 (ii)
Example 23 (i) Important
Example 23 (ii)
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Example 25 Important Deleted for CBSE Board 2022 Exams
Last updated at March 16, 2017 by Teachoo
Example 7 (Long division) Divide the polynomial 3x4 – 4x3 – 3x – 1 by x – 1. By long division Example 7 (Remainder theorem) Divide the polynomial 3x4 – 4x2 – 3x – 1 by x – 1. Dividing 3x4 – 4x2 – 3x – 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = 3x4 – 4x2 – 3x – 1 Putting x = 1 p(1) = 3(1)4 - 4(1)2 – 3(1) – 1 = 3(1) – 4(1) – 3 – 1 = 3 – 4 – 3 – 1 = –5 Thus, remainder = p(1) = –5