Example 7 - Divide the polynomial 3x4 - 4x3 - 3x - 1 by x - 1 - Remainder Theoram

Example 7 - Chapter 2 Class 9 Polynomials - Part 2

Example 7 - Chapter 2 Class 9 Polynomials - Part 3

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Transcript

Question 2 (Long division) Divide the polynomial 3x4 – 4x3 – 3x – 1 by x – 1. By long division Question 2 (Remainder theorem) Divide the polynomial 3x4 – 4x2 – 3x – 1 by x – 1. Dividing 3x4 – 4x2 – 3x – 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = 3x4 – 4x2 – 3x – 1 Putting x = 1 p(1) = 3(1)4 - 4(1)2 – 3(1) – 1 = 3(1) – 4(1) – 3 – 1 = 3 – 4 – 3 – 1 = –5 Thus, remainder = p(1) = –5

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.