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Example 8 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at March 22, 2023 by Teachoo
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Transcript
Example 8 (Method 1) Find the remainder obtained on dividing π(π₯)=π₯^3+1 by π₯+1 Dividing π^π+π by π+π Step 1: Putting Divisor = 0 x + 1 = 0 x = β1 Step 2: Let π(π₯)=π₯^3+1 Putting x = β1 π(βπ)=γ(βπ)γ^3+1 =β1+1 =0 Thus, Remainder =π(βπ)=π Example 8 (Method 2) Find the remainder obtained on dividing π(π₯)=π₯^3+1 by π₯+1 By long division Hence, the remainder is 0
