Question 3 - Examples - Chapter 2 Class 9 Polynomials

Last updated at Dec. 16, 2024 by

Question 3 - Find remainder obtained on dividing p(x) = x3 + 1 - Examples

part 2 - Question 3 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

part 3 - Question 3 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

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Question 3 (Method 1) Find the remainder obtained on dividing 𝑝(𝑥)=𝑥^3+1 by 𝑥+1 Dividing 𝒙^𝟑+𝟏 by 𝒙+𝟏 Step 1: Putting Divisor = 0 x + 1 = 0 x = −1 Step 2: Let 𝑝(𝑥)=𝑥^3+1 Putting x = −1 𝑝(−𝟏)=〖(−𝟏)〗^3+1 =−1+1 =0 Thus, Remainder =𝒑(−𝟏)=𝟎 Question 3 (Method 2) Find the remainder obtained on dividing 𝑝(𝑥)=𝑥^3+1 by 𝑥+1 By long division Hence, the remainder is 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo