Question 3 - Examples - Chapter 2 Class 9 Polynomials

Last updated at August 5, 2026 by Teachoo

Question 3 - Find remainder obtained on dividing p(x) = x3 + 1 - Examples

part 2 - Question 3 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

part 3 - Question 3 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

Next: Question 4 Important → Remove Ads

Transcript

Question 3 (Method 1) Find the remainder obtained on dividing 𝑝(𝑥)=𝑥^3+1 by 𝑥+1 Dividing 𝒙^𝟑+𝟏 by 𝒙+𝟏 Step 1: Putting Divisor = 0 x + 1 = 0 x = −1 Step 2: Let 𝑝(𝑥)=𝑥^3+1 Putting x = −1 𝑝(−𝟏)=〖(−𝟏)〗^3+1 =−1+1 =0 Thus, Remainder =𝒑(−𝟏)=𝟎 Question 3 (Method 2) Find the remainder obtained on dividing 𝑝(𝑥)=𝑥^3+1 by 𝑥+1 By long division Hence, the remainder is 0

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.

Class 6

Class 7

Class 8

Class 9

Class 10

Class 11

Class 12

Courses

Interesting

Popular