Example 18 - Factorize: (i) 49a2 + 70ab + 25b2 (ii) 25/9 - Identity I - IV

  1. Chapter 2 Class 9 Polynomials
  2. Serial order wise
Ask Download

Transcript

Example 18 Factorize: 49a2 + 70ab + 25b2 49a2 + 70ab + 25b2 = 72 a2 + 70ab + 52 b2 = (7a)2 + 70ab + (5b)2 = (7a)2 + (5b)2 + 2(7a) (5b) Using Identity (x + y)2 = x2 + y2 + 2xy where x = 7a and y = 5b = (7a + 5b)2 = (7a + 5b) (7a + 5b) Example 18 Factorize: (ii) 25/4 x2 – y2/9 25/4 x2 – y2/9 = 5^2/2^2 x2 – y2/3^2 = (5/2 𝑥)^2 – (y/3)^2 Using identity (a + b) (a – b) = a2 – b2 Where a = 5/2x , b = 𝑦/3 = (5/2 x+y/3) (5/2 x−y/3)

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.
Jail