Example 6 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at July 12, 2018 by Teachoo
Examples
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Example 1 (ii)
Example 1 (iii) Important
Example 2 (i)
Example 2 (ii)
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Example 3 Important
Example 4
Example 5 Important
Example 6 You are here
Example 7 Important
Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
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Example 11 Important
Example 12 Important
Example 13 Important
Example 14
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Example 16 (i)
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Example 18 (i) Important
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Example 23 (i) Important
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Example 24 Important
Example 25 Important Deleted for CBSE Board 2022 Exams
Transcript
Example 6 Divide the polynomial x + 3x2 – 1 by x + 1. By long division: We divide 3x2 + x – 1 by x + 1 We follow these steps 1. We multiply by 3x 2. The remainder will be the difference of 3x2 + x, and 3x2 + 3x i.e. -2x - 1 3. So, we multiply by -2 4. Then, the remainder will be difference of -2x - 1 and -2x - 2 5. Remainder is +1
