Example 6 - Chapter 2 Class 9 Polynomials

Last updated at Dec. 13, 2024 by

Example 6 - Examine whether x + 2 is a factor of x3 + 3x2 - Examples

part 2 - Example 6 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials
part 3 - Example 6 - Examples - Serial order wise - Chapter 2 Class 9 Polynomials

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Example 6 Examine whether x + 2 is a factor of x3 + 3x2 + 5x + 6 and of 2x + 4. First checking whether x + 2 is a factor of x3 + 3x2 + 5x + 6 Finding remainder when x3 + 3x2 + 5x + 6 is divided by x + 2 Step 1: Put Divisor = 0 x + 2 = 0 x = 2 Step 2: Let p(x) = x3 + 3x2 + 5x + 6 Putting x = 2 p( 2) = ( 2)3 + 3( 2)2 + 5( 2) + 6 = 8 + 12 10 + 6 = 0 Remainder = p( 2) = 0 Since remainder is zero x + 2 is a factor of x3 + 3x2 + 5x + 6 Checking whether x + 2 is a factor of 2x + 4 Finding remainder when 2x + 4 is divided by x + 2 Step 1: Put Divisor = 0 x + 2 = 0 x = 2 Step 2: Let p(x) = 2x + 4 Putting x = 2 p( 2) = 2( 2) + 4 = 4 + 4 = 0 Remainder = p( 2) = 0 Since remainder is zero x + 2 is a factor of 2x + 4

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo