Example 11 - Chapter 2 Class 9 Polynomials (Term 2)
Last updated at Aug. 25, 2021 by Teachoo
Examples
Example 1 (i)
Example 1 (ii)
Example 1 (iii) Important
Example 2 (i)
Example 2 (ii)
Example 2 (iii)
Example 3 Important
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Example 5 Important
Example 6
Example 7 Important
Example 8 Deleted for CBSE Board 2022 Exams
Example 9 Important Deleted for CBSE Board 2022 Exams
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Example 11 Important You are here
Example 12 Important
Example 13 Important
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Example 15 Important
Example 16 (i)
Example 16 (ii)
Example 17
Example 18 (i) Important
Example 18 (ii)
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Example 21 Important
Example 22 (i)
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Example 23 (i) Important
Example 23 (ii)
Example 24 Important
Example 25 Important Deleted for CBSE Board 2022 Exams
Transcript
Example 11 Examine whether x + 2 is a factor of x3 + 3x2 + 5x + 6 and of 2x + 4. First checking whether x + 2 is a factor of x3 + 3x2 + 5x + 6 Finding remainder when x3 + 3x2 + 5x + 6 is divided by x + 2 Step 1: Put Divisor = 0 x + 2 = 0 x = 2 Step 2: Let p(x) = x3 + 3x2 + 5x + 6 Putting x = 2 p( 2) = ( 2)3 + 3( 2)2 + 5( 2) + 6 = 8 + 12 10 + 6 = 0 Remainder = p( 2) = 0 Since remainder is zero x + 2 is a factor of x3 + 3x2 + 5x + 6 Checking whether x + 2 is a factor of 2x + 4 Finding remainder when 2x + 4 is divided by x + 2 Step 1: Put Divisor = 0 x + 2 = 0 x = 2 Step 2: Let p(x) = 2x + 4 Putting x = 2 p( 2) = 2( 2) + 4 = 4 + 4 = 0 Remainder = p( 2) = 0 Since remainder is zero x + 2 is a factor of 2x + 4
