Ex 11.3, 14 (a) - Chapter 11 Class 12 Three Dimensional Geometry

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Ex 11.3, 14 In the following cases, find the distance of each of the given points from the corresponding given plane. The distance of the point (x1, y1, z1) from the plane Ax + By + Cz = D is |(𝑨𝒙_𝟏 + 〖𝑩𝒚〗_𝟏 +〖 𝑪𝒛〗_𝟏 − 𝑫)/√(𝑨^𝟐 + 𝑩^𝟐 + 𝑪^𝟐 )| Given, the point is (0, 0, 0) So, 𝑥_1 = 0, 𝑦_1 = 0, 𝑧_1 = 0 and the equation of plane is 3x − 4y + 12z = 3 Comparing with Ax + By + Cz = D, A = 3, B = −4, C = 12, D = 3 Now, Distance of point from the plane is = |((3 × 0) + (−4 × 0) + (12 × 0) − 3)/( √(3^2 + (−4)^2 + 〖12〗^2 ))| = |(0 + 0 + 0 − 3)/( √(9 + 16 + 144))| = |3/( √169)| = 𝟑/𝟏𝟑