Check sibling questions

Ex 11.3, 14 (a) - Chapter 11 Class 12 Three Dimensional Geometry (Term 2)

Last updated at Aug. 18, 2020 by

Ex 11.3, 14 (a) - Find distance of (0, 0, 0) from plane 3x-4y+12z=3

Ex 11.3, 14 (a) - Chapter 11 Class 12 Three Dimensional Geometry - Part 2

Β 

Transcript

Ex 11.3, 14 In the following cases, find the distance of each of the given points from the corresponding given plane. The distance of the point (x1, y1, z1) from the plane Ax + By + Cz = D is |(𝑨𝒙_𝟏 + γ€–π‘©π’šγ€—_𝟏 +γ€– π‘ͺ𝒛〗_𝟏 βˆ’ 𝑫)/√(𝑨^𝟐 + 𝑩^𝟐 + π‘ͺ^𝟐 )| Given, the point is (0, 0, 0) So, π‘₯_1 = 0, 𝑦_1 = 0, 𝑧_1 = 0 and the equation of plane is 3x βˆ’ 4y + 12z = 3 Comparing with Ax + By + Cz = D, A = 3, B = βˆ’4, C = 12, D = 3 Now, Distance of point from the plane is = |((3 Γ— 0) + (βˆ’4 Γ— 0) + (12 Γ— 0) βˆ’ 3)/( √(3^2 + (βˆ’4)^2 + γ€–12γ€—^2 ))| = |(0 + 0 + 0 βˆ’ 3)/( √(9 + 16 + 144))| = |3/( √169)| = πŸ‘/πŸπŸ‘

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.