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Plane
Last updated at August 13, 2026 by Teachoo
Ā
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Transcript
Question 6 (Introduction) Find the equations of the planes that passes through three points. (a) (1, 1, ā 1), (6, 4, ā 5), (ā 4, ā 2, 3) Vector equation of a plane passing through three points with position vectors š ā, š ā, š ā is ("r" ā ā š ā) . [(š āāš ā)Ć(š āāš ā)] = 0 Question 6 Find the equations of the planes that passes through three points. (a) (1, 1, ā1), (6, 4, ā5), (ā4, ā2, 3) Vector equation of a plane passing through three points with position vectors š ā, š ā, š ā is ("r" ā ā š ā) . [(š āāš ā)Ć(š āāš ā)] = 0 Now, the plane passes through the points (š ā ā š ā) = (6š Ģ + 4š Ģ ā 5š Ģ) ā (1š Ģ + 1š Ģ ā 1š Ģ) = (6 ā1)š Ģ + (4 ā 1)š Ģ + (ā5 ā (ā1)) š Ģ = 5š Ģ + 3š Ģ ā 4š Ģ A (1, 1, ā1) š ā = 1š Ģ + 1š Ģ ā 1š Ģ B (6, 4, ā5) š ā = 6š Ģ + 4š Ģ ā 5š Ģ C ( ā4, ā2, 3) š ā = ā4š Ģ ā 2š Ģ + 3š Ģ (š ā ā š ā) = (ā4š Ģ ā 2š Ģ + 3š Ģ) ā (1š Ģ + 1š Ģ ā 1š Ģ) = (ā4 ā 1)š Ģ +(ā2 ā 1)š Ģ + (3 ā (ā1)) š Ģ = ā5š Ģ ā 3š Ģ + 4š Ģ (š ā ā š ā) Ć (š ā ā š ā) = |ā 8(š Ģ&š Ģ&š Ģ@5&3&ā4@ā5&ā3&4)| = ā |ā 8(š Ģ&š Ģ&š Ģ@5&3&ā4@ 5& 3&ā4)| = š ā This implies, the three points are collinear. Using property: Since the two rows of the determinant are same, the value of determinant is zero. ā“ Vector equation of plane is [š āā(š Ģ+š Ģ āš Ģ )] . 0 ā = 0 Since, the above equation is satisfied for all values of š ā, Therefore, there will be infinite planes passing through the given 3 collinear points.