Ex 11.3

Ex 11.3, 1 (a)

Ex 11.3, 1 (b)

Ex 11.3, 1 (c) Important

Ex 11.3, 1 (d) Important

Ex 11.3, 2

Ex 11.3, 3 (a)

Ex 11.3, 3 (b)

Ex 11.3, 3 (c) Important

Ex 11.3, 4 (a) Important

Ex 11.3, 4 (b)

Ex 11.3, 4 (c)

Ex 11.3, 4 (d) Important

Ex 11.3, 5 (a) Important

Ex 11.3, 5 (b)

Ex 11.3, 6 (a) Important

Ex 11.3, 6 (b)

Ex 11.3, 7

Ex 11.3, 8

Ex 11.3, 9 You are here

Ex 11.3, 10 Important

Ex 11.3, 11 Important

Ex 11.3, 12 Important Deleted for CBSE Board 2022 Exams

Ex 11.3, 13 (a) Important Deleted for CBSE Board 2022 Exams

Ex 11.3, 13 (b) Important

Ex 11.3, 13 (c)

Ex 11.3, 13 (d)

Ex 11.3, 13 (e) Deleted for CBSE Board 2022 Exams

Ex 11.3, 14 (a) Important

Ex 11.3, 14 (b)

Ex 11.3, 14 (c)

Ex 11.3, 14 (d) Important

Chapter 11 Class 12 Three Dimensional Geometry (Term 2)

Serial order wise

Last updated at May 29, 2018 by Teachoo

Ex 11.3, 9 Find the equation of the plane through the intersection of the planes 3x y + 2z 4 = 0 and x + y + z 2 = 0 and the point (2, 2, 1). Equation of a plane passing through the intersection of planes A1x + B1y + C1z = d1 and A2x + B2y + C2z = d2 and through the point (x1, y1, z1) is (A1x + B1y + C1z d1) + (A2x + B2y + C2z d2) = 0 Given, plane passes through Equation of plane is (3x 1y + 2z 4) + (1x + 1y + 1z 2) = 0 3x y + 2z 4 + x + y + z 2 = 0 (3 + ) x + ( 1 + )y + (2 + )z + ( 4 2 ) = 0 We now find the value of The plane passes through (2, 2, 1) Putting (2, 2, 1) in (1), (3 + ) x + ( 1 + )y + (2 + )z + ( 4 2 ) = 0 (3 + ) 2 + ( 1 + ) 2 + (2 + ) 1 + ( 4 2 ) = 0 6 + 2 2 + 2 + 2 + 4 2 = 0 3 + 2 = 0 3 = 2 = Putting value of in (1), (3 + ) x + ( 1 + )y + (2 + )z + ( 4 2 ) = 0 3+ 2 3 x + 1+ 2 3 y + 2+ 2 3 z + 4 2 2 3 = 0 3 2 3 + 1 2 3 y + 2 2 3 z + 4+ 4 3 = 0 7 3 5 3 + 4 3 8 3 = 0 1 3 (7x 5y + 4z 8) = 0 7x 5y + 4z 8 = 0 The equation of plane is 7x 5y + 4z 8 = 0