Question 7 - Plane - Chapter 11 Class 12 Three Dimensional Geometry

Last updated at Dec. 16, 2024 by

Ex 11.3, 7 - Find intercepts cut off by plane 2x + y - z = 5 - Ex 11.3

Ex 11.3, 7 - Chapter 11 Class 12 Three Dimensional Geometry - Part 2

Remove Ads

Transcript

Question 7 Find the intercepts cut off by the plane 2x + y – z = 5. The equation of a plane with intercepts 𝑎, b, c on x, y, and z – axis respectively is 𝒙﷮𝒂﷯ + 𝒚﷮𝒃﷯ + 𝒛﷮𝒄﷯ = 1 Given, equation of plane is 2x + y – z = 5 Dividing by 5 2𝑥 + 𝑦 − 𝑧﷮5﷯ = 5﷮5﷯ 2𝑥﷮5﷯ + 𝑦﷮5﷯ − 𝑧﷮5﷯ = 1 𝑥﷮ 5﷮2﷯﷯﷯ + 𝑦﷮5﷯ + 𝑧﷮(−5)﷯ = 1 Comparing above equation with (1) a = 𝟓﷮𝟐﷯ , b = 5 , c = −5

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo