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Ex 11.3, 7 - Chapter 11 Class 12 Three Dimensional Geometry (Term 2)
Last updated at May 29, 2018 by Teachoo
Ex 11.3
Ex 11.3, 1 (a)
Ex 11.3, 1 (b)
Ex 11.3, 1 (c) Important
Ex 11.3, 1 (d) Important
Ex 11.3, 2
Ex 11.3, 3 (a)
Ex 11.3, 3 (b)
Ex 11.3, 3 (c) Important
Ex 11.3, 4 (a) Important
Ex 11.3, 4 (b)
Ex 11.3, 4 (c)
Ex 11.3, 4 (d) Important
Ex 11.3, 5 (a) Important
Ex 11.3, 5 (b)
Ex 11.3, 6 (a) Important
Ex 11.3, 6 (b)
Ex 11.3, 7 You are here
Ex 11.3, 8
Ex 11.3, 9
Ex 11.3, 10 Important
Ex 11.3, 11 Important
Ex 11.3, 12 Important Deleted for CBSE Board 2022 Exams
Ex 11.3, 13 (a) Important Deleted for CBSE Board 2022 Exams
Ex 11.3, 13 (b) Important
Ex 11.3, 13 (c)
Ex 11.3, 13 (d)
Ex 11.3, 13 (e) Deleted for CBSE Board 2022 Exams
Ex 11.3, 14 (a) Important
Ex 11.3, 14 (b)
Ex 11.3, 14 (c)
Ex 11.3, 14 (d) Important
Chapter 11 Class 12 Three Dimensional Geometry (Term 2)
Serial order wise
Transcript
Ex 11.3, 7 Find the intercepts cut off by the plane 2x + y – z = 5. The equation of a plane with intercepts 𝑎, b, c on x, y, and z – axis respectively is 𝒙𝒂 + 𝒚𝒃 + 𝒛𝒄 = 1 Given, equation of plane is 2x + y – z = 5 Dividing by 5 2𝑥 + 𝑦 − 𝑧5 = 55 2𝑥5 + 𝑦5 − 𝑧5 = 1 𝑥 52 + 𝑦5 + 𝑧(−5) = 1 Comparing above equation with (1) a = 𝟓𝟐 , b = 5 , c = −5
