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Ex 11.3, 3 (a) - Chapter 11 Class 12 Three Dimensional Geometry (Term 2)
Last updated at Aug. 24, 2021 by Teachoo
Ex 11.3
Ex 11.3, 1 (a)
Ex 11.3, 1 (b)
Ex 11.3, 1 (c) Important
Ex 11.3, 1 (d) Important
Ex 11.3, 2
Ex 11.3, 3 (a) You are here
Ex 11.3, 3 (b)
Ex 11.3, 3 (c) Important
Ex 11.3, 4 (a) Important
Ex 11.3, 4 (b)
Ex 11.3, 4 (c)
Ex 11.3, 4 (d) Important
Ex 11.3, 5 (a) Important
Ex 11.3, 5 (b)
Ex 11.3, 6 (a) Important
Ex 11.3, 6 (b)
Ex 11.3, 7
Ex 11.3, 8
Ex 11.3, 9
Ex 11.3, 10 Important
Ex 11.3, 11 Important
Ex 11.3, 12 Important Deleted for CBSE Board 2022 Exams
Ex 11.3, 13 (a) Important Deleted for CBSE Board 2022 Exams
Ex 11.3, 13 (b) Important
Ex 11.3, 13 (c)
Ex 11.3, 13 (d)
Ex 11.3, 13 (e) Deleted for CBSE Board 2022 Exams
Ex 11.3, 14 (a) Important
Ex 11.3, 14 (b)
Ex 11.3, 14 (c)
Ex 11.3, 14 (d) Important
Chapter 11 Class 12 Three Dimensional Geometry (Term 2)
Serial order wise
Transcript
Ex 11.3, 3 Find the Cartesian equation of the following planes: (a) πο·― . ( πο·― + πο·― β πο·―) = 2 Putting πο·― = x πο·― + y πο·― + z πο·― in equation πο·―.( πο·― + πο·― β πο·―) = 2 (x πο·― + y πο·― + z πο·―). ( πο·― + πο·― β πο·―) = 2 (x Γ 1) + (y Γ 1) + (z Γ β1) = 2 x + y β z = 2 is the cartesian equation of the given plane.
