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Ex 16.3
Ex 16.3, 2
Ex 16.3, 3 (i) Important
Ex 16.3, 3 (ii)
Ex 16.3, 3 (iii)
Ex 16.3, 3 (iv)
Ex 16.3, 3 (v)
Ex 16.3, 4 Important
Ex 16.3 ,5 Important
Ex 16.3, 6
Ex 16.3, 7 Important
Ex 16.3, 8 Important
Ex 16.3, 9
Ex 16.3, 10
Ex 16.3, 11 Important
Ex 16.3, 12 (i)
Ex 16.3, 12 (ii) Important
Ex 16.3, 13
Ex 16.3, 14 Important
Ex 16.3, 15 Important
Ex 16.3, 16 Important
Ex 16.3, 17 You are here
Ex 16.3, 18
Ex 16.3, 19
Ex 16.3, 20 Important
Ex 16.3, 21 Important
Last updated at March 16, 2023 by Teachoo
Ex 16.3, 17 A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (i) P(not A), P(A) = 0.42 P(not A) = 1 P(A) = 1 0.42 = 0.58 Ex 16.3, 17 A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (ii) P (not B) P(B) = 0.48 P(not B) = 1 P(B) = 1 0.48 = 0.52 Ex 16.3, 17 A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (iii) P(A or B). P(A or B) = P(A B) We know that P(A B) = P(A) + P(B) P(A B) Putting values P(A B) = 0.42 + 0.48 0.16 = 0.74 Hence, P(A or B) = 0.74