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Ex 14.2
Ex 14.2, 2
Ex 14.2, 3 (i) Important
Ex 14.2, 3 (ii)
Ex 14.2, 3 (iii)
Ex 14.2, 3 (iv)
Ex 14.2, 3 (v)
Ex 14.2, 4 Important
Ex 14.2 ,5 Important
Ex 14.2, 6
Ex 14.2, 7 Important
Ex 14.2, 8 Important
Ex 14.2, 9
Ex 14.2, 10
Ex 14.2, 11 Important
Ex 14.2, 12 (i)
Ex 14.2, 12 (ii) Important
Ex 14.2, 13
Ex 14.2, 14 Important
Ex 14.2, 15 Important
Ex 14.2, 16 Important
Ex 14.2, 17 You are here
Ex 14.2, 18
Ex 14.2, 19
Ex 14.2, 20 Important
Ex 14.2, 21 Important
Ex 14.2
Last updated at May 29, 2023 by Teachoo
Ex 14.2, 17 A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (i) P(not A), P(A) = 0.42 P(not A) = 1 P(A) = 1 0.42 = 0.58 Ex 14.2, 17 A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (ii) P (not B) P(B) = 0.48 P(not B) = 1 P(B) = 1 0.48 = 0.52 Ex 14.2, 17 A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (iii) P(A or B). P(A or B) = P(A B) We know that P(A B) = P(A) + P(B) P(A B) Putting values P(A B) = 0.42 + 0.48 0.16 = 0.74 Hence, P(A or B) = 0.74